Math Problem Statement

(9)^{\sqrt[3]{\log_2 3}} and (8)^{4 \log_{27} 4}

Solution

The image contains two logarithmic expressions to be calculated under the heading "Hitung," which means "Calculate" in Indonesian:

  1. a. (9)log233\text{a.} \ (9)^{\sqrt[3]{\log_2 3}}
  2. b. (8)4log274\text{b.} \ (8)^{4 \log_{27} 4}

Let’s solve each one step by step.

Part (a): (9)log233(9)^{\sqrt[3]{\log_2 3}}

  1. Start by expressing 9 as a power of 3: 9=329 = 3^2 So the expression becomes: [ (3^2)^{\sqrt[3]{\log_2 3}} = 3^{2\sqrt[3]{\log_2 3}} ]
  2. The result is simplified, but it can remain in this form for now. This expression is difficult to simplify further without numerical approximation.

Part (b): (8)4log274(8)^{4 \log_{27} 4}

  1. Express 8 and 27 in terms of powers of 2 and 3: 8=23,27=338 = 2^3, \quad 27 = 3^3 So the expression becomes: (23)4log334=212log34/3(2^3)^{4 \log_{3^3} 4} = 2^{12 \log_3 4 / 3}
  2. Use the property of logarithms: logabc=1blogac\log_{a^b} c = \frac{1}{b} \log_a c, which simplifies the exponent: 24log342^{4 \log_3 4}
  3. Finally, apply the logarithmic identity alogbc=clogbaa^{\log_b c} = c^{\log_b a} to simplify the expression: 24log34=4log324=4log3162^{4 \log_3 4} = 4^{\log_3 2^4} = 4^{\log_3 16}

Let me know if you would like further clarification or a more detailed explanation!


Here are 5 related questions for practice:

  1. What is the value of log216\log_2 16?
  2. Simplify (27)log33(27)^{\log_3 3}.
  3. Calculate (4)log216(4)^{\log_2 16}.
  4. How do you simplify alogbca^{\log_b c} using logarithmic properties?
  5. Evaluate (25)log55(25)^{\log_5 5}.

Tip: Always remember logarithmic properties such as alogbc=clogbaa^{\log_b c} = c^{\log_b a}, as they are useful for simplifying complex expressions.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Exponentiation
Algebraic manipulation

Formulas

a^{\log_b c} = c^{\log_b a}
\log_{a^b} c = \frac{1}{b} \log_a c

Theorems

Logarithmic identity
Exponent rules

Suitable Grade Level

Grades 10-12