Dan is fourteen years older than Marge. Eight years ago, Dan was three times as old as Marge. Find
their present age.

Let's solve this problem step by step.

Let Marge's present age be \( M \). Since Dan is 14 years older than Marge, Dan's present age will be \( M + 14 \).

Eight years ago, Dan's age would have been \( (M + 14) - 8 = M + 6 \), and Marge's age would have been \( M - 8 \).

According to the problem, eight years ago, Dan was three times as old as Marge. Therefore, we can set up the following equation:

\[
M + 6 = 3(M - 8)
\]

### Solving the Equation:

1. Expand the right side of the equation:
   \[
   M + 6 = 3M - 24
   \]

2. Subtract \( M \) from both sides:
   \[
   6 = 2M - 24
   \]

3. Add 24 to both sides:
   \[
   30 = 2M
   \]

4. Divide both sides by 2:
   \[
   M = 15
   \]

So, Marge's present age is 15 years.

Now, find Dan's age:
\[
D = M + 14 = 15 + 14 = 29
\]

So, Dan is 29 years old.

### Final Answer:
- Marge is 15 years old.
- Dan is 29 years old.

Do you want more details or have any questions?

Here are 5 related questions to explore further:

1. If Dan was twice as old as Marge 10 years ago, what would be their current ages?
2. How old will Marge be in 5 years?
3. What is the difference in their ages now, and will it change in the future?
4. If Dan and Marge's ages add up to 50, what are their current ages?
5. What was Marge's age 5 years ago?

**Tip:** When dealing with age problems, set up equations based on relationships given in the problem, and solve them step by step.

Learn how to solve the age problem where Dan is fourteen years older than Marge. Eight years ago, Dan was three times as old as Marge. Find their current ages with a step-by-step solution. Suitable for students in Grades 6-8.

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