Seven Years from now, mary will be three times as old as she was fifteen years ago. how old is she now

Let's solve this step by step.

1. **Define the variable**:
   Let \( x \) represent Mary's current age.

2. **Set up the equation based on the problem statement**:
   - "Seven years from now" means we add 7 to her current age, so her age will be \( x + 7 \).
   - "Fifteen years ago" means we subtract 15 from her current age, so her age was \( x - 15 \).
   - The problem states that seven years from now, Mary will be three times as old as she was fifteen years ago. Thus, the equation becomes:
   \[
   x + 7 = 3(x - 15)
   \]

3. **Solve the equation**:
   \[
   x + 7 = 3(x - 15)
   \]

   Distribute the 3 on the right side:
   \[
   x + 7 = 3x - 45
   \]

   Subtract \( x \) from both sides to isolate terms with \( x \) on one side:
   \[
   7 = 2x - 45
   \]

   Add 45 to both sides to solve for \( 2x \):
   \[
   52 = 2x
   \]

   Divide by 2 to find \( x \):
   \[
   x = 26
   \]

4. **Conclusion**:
   Mary is currently **26 years old**.

Would you like further details or have any questions about this solution?

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Here are some related questions that expand on this topic:

1. What would be Mary's age in 10 years?
2. If Mary was twice as old as someone 10 years ago, how old is that person now?
3. How do you solve an age problem with two variables?
4. How do you translate word problems into algebraic equations?
5. What are some common age-related word problems in algebra?

**Tip:** When dealing with word problems, clearly define what each variable represents and translate the statements step-by-step into mathematical equations.

Explore how to solve the age problem where Mary's age in seven years will be three times what it was fifteen years ago. Step-by-step solution provided, suitable for Grades 7-9.

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