Math Problem Statement

関数 y = 4x^2 について、x の値が -3 から a まで増加するときの変化の割合は 12 になります。a の値を求めなさい。

Solution

The given problem in Japanese reads as follows:

「関数 y=4x2y = 4x^2 について、xx の値が 3-3 から aa まで増加するときの変化の割合は 12 になります。aa の値を求めなさい。」

Translation: For the function y=4x2y = 4x^2, when the value of xx increases from 3-3 to aa, the rate of change is 12. Find the value of aa.

Solution:

The rate of change of the function y=4x2y = 4x^2 as xx changes from x1=3x_1 = -3 to x2=ax_2 = a can be computed using the average rate of change formula:

Rate of change=y(x2)y(x1)x2x1\text{Rate of change} = \frac{y(x_2) - y(x_1)}{x_2 - x_1}

Substitute the given function y=4x2y = 4x^2 and the points x1=3x_1 = -3 and x2=ax_2 = a:

Rate of change=4a24(3)2a(3)\text{Rate of change} = \frac{4a^2 - 4(-3)^2}{a - (-3)}

Since 4(3)2=4×9=364(-3)^2 = 4 \times 9 = 36, the equation becomes:

Rate of change=4a236a+3\text{Rate of change} = \frac{4a^2 - 36}{a + 3}

We are told that the rate of change is 12, so:

4a236a+3=12\frac{4a^2 - 36}{a + 3} = 12

Now, solve this equation for aa.

  1. Multiply both sides by a+3a + 3 to eliminate the denominator:

4a236=12(a+3)4a^2 - 36 = 12(a + 3)

  1. Expand the right-hand side:

4a236=12a+364a^2 - 36 = 12a + 36

  1. Move all terms to one side:

4a212a72=04a^2 - 12a - 72 = 0

  1. Divide through by 4 to simplify:

a23a18=0a^2 - 3a - 18 = 0

  1. Solve this quadratic equation using the quadratic formula:

a=(3)±(3)24(1)(18)2(1)a = \frac{-(-3) \pm \sqrt{(-3)^2 - 4(1)(-18)}}{2(1)}

a=3±9+722a = \frac{3 \pm \sqrt{9 + 72}}{2}

a=3±812a = \frac{3 \pm \sqrt{81}}{2}

a=3±92a = \frac{3 \pm 9}{2}

Thus, we get two solutions:

a=3+92=6ora=392=3a = \frac{3 + 9}{2} = 6 \quad \text{or} \quad a = \frac{3 - 9}{2} = -3

Since the problem specifies that xx increases from 3-3, we discard a=3a = -3, and the solution is:

a=6a = 6

Final Answer:

The value of aa is 66.


Would you like further details or have any questions? Here are some related questions:

  1. What is the geometric interpretation of the average rate of change?
  2. How does the quadratic formula work in solving ax2+bx+c=0ax^2 + bx + c = 0?
  3. Can you explain how to check the solution to the quadratic equation step by step?
  4. Why do we discard the negative solution a=3a = -3 in this problem?
  5. What is the significance of the rate of change in a quadratic function?

Tip: Always remember to carefully substitute values and simplify equations step by step when working with algebraic expressions.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Functions
Rate of Change

Formulas

Average rate of change formula: (y(x2) - y(x1)) / (x2 - x1)
Quadratic formula: x = (-b ± √(b² - 4ac)) / 2a

Theorems

Quadratic equation solution methods

Suitable Grade Level

Grades 9-11