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To solve this problem, we are given a rectangular table with:

- Length: \( 2\sqrt{12} \)
- Width: \( \sqrt{3} \)

We need to calculate the area of the table using the formula for the area of a rectangle:

\[
\text{Area} = \text{Length} \times \text{Width}
\]

### Solution:

1. **Step 1: Simplify the values**  
   The length is \( 2\sqrt{12} \) and the width is \( \sqrt{3} \).
   - Simplify \( \sqrt{12} \):
     \[
     \sqrt{12} = \sqrt{4 \times 3} = 2\sqrt{3}
     \]
     Therefore, the length becomes:
     \[
     2\sqrt{12} = 2 \times 2\sqrt{3} = 4\sqrt{3}
     \]

2. **Step 2: Multiply the length and width**  
   Now, calculate the area:
   \[
   \text{Area} = 4\sqrt{3} \times \sqrt{3} = 4 \times (\sqrt{3} \times \sqrt{3}) = 4 \times 3 = 12
   \]

### Conclusion:

The area of the table is \( \boxed{12} \) square units.

Would you like further details or explanations? Here are some related questions:

1. How do you simplify square roots like \( \sqrt{12} \)?
2. Why does \( \sqrt{3} \times \sqrt{3} = 3 \)?
3. Can the area formula change for non-rectangular shapes?
4. How is area used in real-life scenarios?
5. What other geometric properties can be calculated for rectangles?

**Tip**: Always simplify square roots as much as possible before performing further calculations to make the process easier!

A rectangular table has a length of 2√12 and width of √3. What is the area of the table?

Learn how to find the area of a rectangular table with a length of 2√12 and width of √3. This problem involves simplifying square roots and calculating the area using the formula for a rectangle. Suitable for Grades 7-9.

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