Math Problem Statement

Given the points A(-3, -2), B(2, -2), C(5, 2), and D(0, 2), determine if the quadrilateral ABCD is a parallelogram, rectangle, rhombus, or square. Provide reasoning for each answer.

Solution

Let's solve the questions based on the points provided in the image: A(3,2)A(-3, -2), B(2,2)B(2, -2), C(5,2)C(5, 2), and D(0,2)D(0, 2).


Step 1: Check if ABCD is a parallelogram

A quadrilateral is a parallelogram if opposite sides are parallel. This requires checking slopes of opposite sides:

  1. Slope of AB: slopeAB=y2y1x2x1=2(2)2(3)=05=0\text{slope}_{AB} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-2 - (-2)}{2 - (-3)} = \frac{0}{5} = 0

  2. Slope of CD: slopeCD=2205=05=0\text{slope}_{CD} = \frac{2 - 2}{0 - 5} = \frac{0}{-5} = 0 Since slopeAB=slopeCD\text{slope}_{AB} = \text{slope}_{CD}, ABCDAB \parallel CD.

  3. Slope of BC: slopeBC=2(2)52=43\text{slope}_{BC} = \frac{2 - (-2)}{5 - 2} = \frac{4}{3}

  4. Slope of AD: slopeAD=2(2)0(3)=43\text{slope}_{AD} = \frac{2 - (-2)}{0 - (-3)} = \frac{4}{3} Since slopeBC=slopeAD\text{slope}_{BC} = \text{slope}_{AD}, BCADBC \parallel AD.

Since opposite sides are parallel, ABCD is a parallelogram.


Step 2: Check if ABCD is a rectangle

A parallelogram is a rectangle if adjacent sides are perpendicular. Check the product of the slopes of ABAB and BCBC:

  1. Product of slopes ABAB and BCBC: slopeABslopeBC=043=0\text{slope}_{AB} \cdot \text{slope}_{BC} = 0 \cdot \frac{4}{3} = 0 Since the product is 00, ABBCAB \perp BC.

  2. Similarly, BCCDBC \perp CD, CDADCD \perp AD, and ADABAD \perp AB (can be verified).

Thus, ABCD is a rectangle.


Step 3: Check if ABCD is a rhombus

A parallelogram is a rhombus if all sides are equal. Use the distance formula to calculate the lengths of all sides:

  1. Length of AB: AB=(2(3))2+(2(2))2=52+02=5AB = \sqrt{(2 - (-3))^2 + (-2 - (-2))^2} = \sqrt{5^2 + 0^2} = 5

  2. Length of BC: BC=(52)2+(2(2))2=32+42=9+16=5BC = \sqrt{(5 - 2)^2 + (2 - (-2))^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = 5

  3. Length of CD: CD=(50)2+(22)2=52+02=5CD = \sqrt{(5 - 0)^2 + (2 - 2)^2} = \sqrt{5^2 + 0^2} = 5

  4. Length of AD: AD=(0(3))2+(2(2))2=32+42=5AD = \sqrt{(0 - (-3))^2 + (2 - (-2))^2} = \sqrt{3^2 + 4^2} = 5

Since all sides are equal, ABCD is a rhombus.


Step 4: Check if ABCD is a square

A quadrilateral is a square if it is both a rectangle and a rhombus. Since ABCDABCD is both a rectangle and a rhombus, ABCD is a square.


Summary:

  1. Is ABCD a parallelogram? Yes.
  2. Is ABCD a rectangle? Yes.
  3. Is ABCD a rhombus? Yes.
  4. Is ABCD a square? Yes.

Would you like more details about any step or further clarification?


Related Questions:

  1. How do you find slopes of lines to verify parallelism?
  2. What makes a parallelogram a rectangle?
  3. How does the distance formula help confirm congruent sides?
  4. Can a shape be both a rectangle and a rhombus but not a square?
  5. What conditions define a square in a coordinate plane?

Tip:

When checking for perpendicularity, always multiply the slopes of two lines. If the result is 1-1 or 00, they are perpendicular!

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Properties of Quadrilaterals

Formulas

Slope formula: (y2 - y1) / (x2 - x1)
Distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2)

Theorems

A quadrilateral is a parallelogram if opposite sides are parallel.
A parallelogram is a rectangle if adjacent sides are perpendicular.
A parallelogram is a rhombus if all sides are equal.
A quadrilateral is a square if it is both a rectangle and a rhombus.

Suitable Grade Level

Grades 9-11