Math Problem Statement

Use the distance formula to show that ABCD is not a square

Use the distance formula to show that ABCD is not a square.

Solution

To determine whether quadrilateral ABCDABCD is a square, we will use the distance formula to calculate the lengths of all four sides of the quadrilateral. For a quadrilateral to be a square, all four sides must be of equal length, and the diagonals must also be equal in length.

Step 1: Identify the coordinates of the vertices

From the image, the approximate coordinates of the vertices are:

  • A=(2,2)A = (-2, 2)
  • B=(1,3)B = (1, 3)
  • C=(2,0)C = (2, 0)
  • D=(1,1)D = (-1, -1)

Step 2: Apply the Distance Formula

The distance formula between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is: d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

  1. Length of ABAB: AB=(1(2))2+(32)2=(3)2+(1)2=9+1=10AB = \sqrt{(1 - (-2))^2 + (3 - 2)^2} = \sqrt{(3)^2 + (1)^2} = \sqrt{9 + 1} = \sqrt{10}

  2. Length of BCBC: BC=(21)2+(03)2=(1)2+(3)2=1+9=10BC = \sqrt{(2 - 1)^2 + (0 - 3)^2} = \sqrt{(1)^2 + (-3)^2} = \sqrt{1 + 9} = \sqrt{10}

  3. Length of CDCD: CD=(2(1))2+(0(1))2=(3)2+(1)2=9+1=10CD = \sqrt{(2 - (-1))^2 + (0 - (-1))^2} = \sqrt{(3)^2 + (1)^2} = \sqrt{9 + 1} = \sqrt{10}

  4. Length of DADA: DA=(1(2))2+(12)2=(1)2+(3)2=1+9=10DA = \sqrt{(-1 - (-2))^2 + (-1 - 2)^2} = \sqrt{(1)^2 + (-3)^2} = \sqrt{1 + 9} = \sqrt{10}

Step 3: Check the Diagonals

For a square, the diagonals should also be equal in length.

  1. Length of ACAC: AC=(2(2))2+(02)2=(4)2+(2)2=16+4=20AC = \sqrt{(2 - (-2))^2 + (0 - 2)^2} = \sqrt{(4)^2 + (-2)^2} = \sqrt{16 + 4} = \sqrt{20}

  2. Length of BDBD: BD=(1(1))2+(3(1))2=(2)2+(4)2=4+16=20BD = \sqrt{(1 - (-1))^2 + (3 - (-1))^2} = \sqrt{(2)^2 + (4)^2} = \sqrt{4 + 16} = \sqrt{20}

Conclusion:

  • All four sides ABAB, BCBC, CDCD, and DADA have the same length 10\sqrt{10}.
  • Both diagonals ACAC and BDBD have the same length 20\sqrt{20}.

Despite all sides and diagonals being equal, this quadrilateral cannot be a square because the lengths of the diagonals should be 2\sqrt{2} times the side length for a true square. Here, the diagonals are longer than this ratio. Therefore, ABCDABCD is a rhombus but not a square.

Would you like further details or have any questions?

Related Questions:

  1. What is the specific condition for a rhombus to be a square?
  2. How do we calculate the angles of quadrilateral ABCDABCD to further confirm its shape?
  3. How does the orientation of a quadrilateral on the coordinate plane affect its classification?
  4. Can you determine the area of quadrilateral ABCDABCD using the coordinates?
  5. What is the significance of the diagonals' lengths in classifying quadrilaterals?

Tip:

To distinguish between a rhombus and a square, remember that a square must have equal diagonals that bisect each other at right angles, whereas a rhombus only requires equal side lengths with diagonals that bisect at any angle.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Quadrilaterals
Rhombus
Square

Formulas

Distance formula: d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Theorems

A square is a quadrilateral with all sides equal and all angles 90 degrees.
The diagonals of a square are equal and bisect each other at right angles.
A rhombus is a quadrilateral with all sides equal, but the diagonals do not necessarily bisect at 90 degrees.

Suitable Grade Level

Grades 9-10