Math Problem Statement

Define an → a as n → ∞. Use this to show that (−1)n doesn’t converge to any real number

Solution

To solve this, let's first explore what the notation means and how to apply it to prove that (1)n(-1)^n does not converge to any real number.

Definition of Convergence

In general, a sequence ana_n converges to a real number aa if:

limnan=a\lim_{n \to \infty} a_n = a

This means that for every positive number ϵ>0\epsilon > 0, there exists an integer NN such that for all n>Nn > N, the absolute difference between ana_n and aa is less than ϵ\epsilon:

ana<ϵ|a_n - a| < \epsilon

In simpler terms, as nn \to \infty, the terms of the sequence ana_n get arbitrarily close to the value aa.

The Sequence (1)n(-1)^n

Now consider the sequence defined by (1)n(-1)^n, which alternates between the values 11 and 1-1:

(1)1=1,(1)2=1,(1)3=1,(1)4=1,(-1)^1 = -1, \quad (-1)^2 = 1, \quad (-1)^3 = -1, \quad (-1)^4 = 1, \quad \ldots

This sequence does not "settle down" to a single value as nn \to \infty, because it keeps switching between 1 and -1.

Showing Non-Convergence

Let's suppose, for the sake of contradiction, that (1)n(-1)^n converges to some real number aa. According to the definition of convergence, as nn \to \infty, the terms of the sequence should get closer and closer to this value aa.

  1. Consider the subsequence where nn is even: (1)2k=1,k=1,2,3,(-1)^{2k} = 1, \quad k = 1, 2, 3, \dots This subsequence converges to 11.

  2. Now consider the subsequence where nn is odd: (1)2k+1=1,k=1,2,3,(-1)^{2k+1} = -1, \quad k = 1, 2, 3, \dots This subsequence converges to 1-1.

For the sequence (1)n(-1)^n to converge to some real number aa, both subsequences must converge to the same value. However, we see that the even subsequence converges to 1, while the odd subsequence converges to -1. This means that the sequence (1)n(-1)^n does not get arbitrarily close to a single real number.

Thus, the sequence does not converge to any real number aa.

Conclusion

The sequence (1)n(-1)^n does not converge to any real number because it alternates between 1 and -1, and the limits of the subsequences (even and odd terms) do not match.

Would you like further details or have any questions?

Related Questions:

  1. What is the formal definition of a convergent sequence?
  2. Can you show an example of a sequence that does converge to a real number?
  3. What is the difference between a divergent sequence and an oscillating sequence?
  4. How does the concept of subsequences help in understanding convergence?
  5. What is the importance of limits in mathematical analysis?

Tip:

When testing for convergence of a sequence, always consider the behavior of subsequences. If two subsequences of the same sequence converge to different values, the sequence itself does not converge.

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Math Problem Analysis

Mathematical Concepts

Sequence Convergence
Limits
Real Analysis

Formulas

lim (n → ∞) a_n = a
|a_n - a| < ε

Theorems

Definition of Convergence of a Sequence

Suitable Grade Level

Undergraduate Mathematics