Math Problem Statement
Using division with remainder, show that any common multiple of a, b is divisible by lcm(a, b). Just use the division with remainder theorem, no gcd
Solution
We are tasked with proving that any common multiple of two integers and is divisible by their least common multiple , using only the division with remainder theorem, and without relying on the greatest common divisor (gcd). Here's a step-by-step proof:
Step 1: Division with Remainder Theorem
The division with remainder theorem states that for any two integers and , there exist unique integers (the quotient) and (the remainder) such that: where .
Step 2: Define the Common Multiple
Let be any common multiple of and . By definition, this means that can be written as: for some integers and . Thus, is divisible by both and .
Step 3: Division of by
We now apply the division with remainder theorem to and . By the theorem, there exist integers (quotient) and (remainder) such that: where .
Step 4: Show the Remainder is Zero
Since is a common multiple of and , both and divide . Therefore, both and must also divide the remainder . This is because if were not zero, then both and would have to divide a number smaller than , which contradicts the definition of the least common multiple.
Since is a non-negative integer smaller than , and both and divide , the only possible value for is 0. Therefore:
Step 5: Conclusion
Since , we have: which shows that is divisible by .
Thus, any common multiple of and is divisible by , completing the proof.
Would you like further details or explanations? Here are 5 questions that could expand on this topic:
- How do you compute the least common multiple of two numbers using prime factorizations?
- Can you prove the relationship between gcd and lcm in terms of divisibility properties?
- How does this proof relate to the concept of the greatest common divisor?
- What role does the remainder play in modular arithmetic, and how does it relate to divisibility?
- How does the Euclidean algorithm relate to the division with remainder theorem?
Tip: The least common multiple of two numbers can also be expressed using their product and gcd: .
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Math Problem Analysis
Mathematical Concepts
Number Theory
Divisibility
Common Multiples
Least Common Multiple (LCM)
Division with Remainder
Formulas
Division with Remainder: m = qn + r, where 0 <= r < n
LCM expression: m = q * lcm(a, b) + r
Theorems
Division with Remainder Theorem
Suitable Grade Level
Grades 9-12