Isaac flips a fair coin 3 times. What is the probability that the coin will come up heads 2 out of 3 times.

To find the probability that Isaac flips a fair coin 3 times and gets exactly 2 heads, we need to follow these steps:

### Step 1: Total Possible Outcomes
Each flip has 2 possible outcomes: heads (H) or tails (T). Since the coin is flipped 3 times, the total number of possible outcomes is:
\[
2^3 = 8
\]
These possible outcomes are: 
\[
\{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT\}
\]

### Step 2: Favorable Outcomes (2 Heads)
Now, we need to count the number of outcomes where exactly 2 heads occur. The favorable outcomes are:
\[
\{HHT, HTH, THH\}
\]
There are 3 favorable outcomes.

### Step 3: Probability Calculation
The probability of getting exactly 2 heads is the ratio of favorable outcomes to the total number of possible outcomes:
\[
P(\text{2 heads}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{3}{8}
\]

Thus, the probability that Isaac gets exactly 2 heads out of 3 flips is \(\frac{3}{8}\), or 0.375.

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Would you like further details on how the calculation works or have any questions? 

Here are 5 follow-up questions to extend the discussion:
1. What is the probability of getting exactly 1 head in 3 flips?
2. How would the probability change if the coin was biased towards heads?
3. What is the probability of getting at least 1 head in 3 flips?
4. What is the probability of getting no heads in 3 flips?
5. How does this problem change if the number of flips increases to 4?

**Tip:** When calculating probabilities of multiple independent events, multiply the probabilities of each individual event if you know their outcomes.

Isaac flips a fair coin 3 times. What is the probability that the coin will come up heads 2 out of 3 times?

Explore how to calculate the probability of getting exactly 2 heads out of 3 flips of a fair coin. This solution includes step-by-step analysis using probability and combinatorics, and is perfect for students in Grades 5-7.

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