The key to solving this problem is understanding that the event being described is the number of heads that appear in a set of three coin tosses. In the original set of tosses, HTH, there are exactly two heads.

The correct answer should also involve two heads, regardless of the order of heads and tails.

• Option A: HHT has two heads and one tail, which matches the number of heads in HTH. This corresponds to the same event.
• Option B: THT also has two heads, so it may seem correct, but it’s focusing on the opposite results rather than the number of heads.
• Option C: HHH has three heads, which is not the same as HTH.
• Option D: HHH has three heads, so this is incorrect.
• Option E: HHT has the same number of heads and tails as HTH.
• Option F: THT has two heads, but the reasoning given is not focused on the number of heads.

Thus, the best answer is E. HHT, because it has the same number of heads and tails as HTH.

Would you like more details on the logic used in probability events?

Here are 5 related questions to further explore:

1. What is the probability of getting exactly two heads in three coin tosses?
2. How many different outcomes are possible when tossing a coin three times?
3. If you toss a coin three times, what is the probability of getting heads on the first and second toss?
4. What does it mean for two events to correspond to the same outcome in probability?
5. How can we use combinations to determine the number of ways to get two heads in three tosses?

Tip: Always break down a problem into simpler events and focus on the critical variables, like the number of heads in this case.