Math Problem Statement

There are 500 light bulbs numbered 1 to 500 arranged in a row. Initially they are all off. Starting with bulb 2, all even numbered bulbs are turned ON. Next starting with 3 and visiting every 3rd bulb it is turned ON if it is OFF and turned OFF if it is ON. This procedure is repeated for every 4th bulb then every fifth bulb and so on up to 500th bulb. Devise an algorithm to determine which bulb glows at the end of above exercise

Solution

To determine which bulbs remain ON at the end of the given exercise, we observe the following:

  1. Each bulb kk is toggled on each step corresponding to its divisors. For instance:

    • Bulb 12 is toggled for steps 1, 2, 3, 4, 6, and 12 (its divisors).
  2. A bulb ends up ON only if it is toggled an odd number of times. A number has an odd number of divisors only if it is a perfect square. For example:

    • 1616 has divisors 1,2,4,8,161, 2, 4, 8, 16, which is odd.
    • 1212 has divisors 1,2,3,4,6,121, 2, 3, 4, 6, 12, which is even.
  3. Hence, the problem reduces to finding all perfect squares from 11 to 500500.

Algorithm:

  1. Initialize a list of size 500500 with all bulbs set to "OFF."
  2. Loop through each number from 1 to 500:
    • Toggle the bulbs corresponding to multiples of the current number.
  3. Return the bulbs that remain ON (those corresponding to perfect squares).

Optimized Insight:

The bulbs remaining ON are only those at positions corresponding to perfect squares n2500n^2 \leq 500. Compute nn such that n2500n^2 \leq 500.

Steps to Find Bulbs:

  1. List all integers nn such that n2500n^2 \leq 500.
  2. Compute the squares: n=1,2,3,,22n = 1, 2, 3, \ldots, 22 (since 222=48422^2 = 484).
  3. Return 12,22,,2221^2, 2^2, \ldots, 22^2.

Python Code:

python
def glowing_bulbs(): perfect_squares = [] n = 1 while n**2 <= 500: perfect_squares.append(n**2) n += 1 return perfect_squares print(glowing_bulbs())

Output:

The bulbs that glow are: 1,4,9,16,25,36,49,64,81,100,121,144,169,196,225,256,289,324,361,400,441,4841, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441, 484.


Would you like details about the implementation or mathematical reasoning? Here are related questions to deepen your understanding:

  1. Why do only perfect squares have an odd number of divisors?
  2. How can you generalize this algorithm for a different number of bulbs or steps?
  3. What is the time complexity of the naive algorithm versus the optimized one?
  4. How does the structure of divisors relate to toggling patterns?
  5. Can this algorithm be extended for prime-based toggle steps?

Tip: To identify perfect squares in a range, consider the sequence of integers squared from 1 upwards.

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Math Problem Analysis

Mathematical Concepts

Number Theory
Divisors
Perfect Squares

Formulas

A number has an odd number of divisors if and only if it is a perfect square.

Theorems

Perfect Square Theorem (odd number of divisors)

Suitable Grade Level

Grades 9-12