https://file.aiquickdraw.com/mathbot/file/1726156129191i22kr7du.jpg

To find the percent error in Jim's measurement, we can use the formula for percent error:

\[
\text{Percent Error} = \frac{|\text{Measured Value} - \text{Actual Value}|}{\text{Actual Value}} \times 100
\]

Given:
- Measured value = 82 inches
- Actual value = 92 inches

Now, applying these values to the formula:

\[
\text{Percent Error} = \frac{|82 - 92|}{92} \times 100
\]

Let's calculate that.The percent error in Jim's measurement is 11%, rounded to the nearest whole percent.

Would you like any further clarification on the solution?

Here are some related questions for practice:
1. If Jim measured the net to be 95 inches, what would the percent error be?
2. How would you calculate the percent error if Jim had measured it as 90 inches?
3. If the actual height of a different object is 50 inches and the measured height is 47 inches, what is the percent error?
4. What does a 0% error imply about the measurement?
5. If the percent error is larger, what does that say about the accuracy of the measurement?

**Tip:** When calculating percent error, always subtract the smaller value from the larger one to avoid negative values.

Jim measures the height of a volleyball net to be 82 in, but its actual height is 92 in. What is the percent error in Jim's measurement? Round to the nearest whole percent.

Learn how to calculate the percent error when Jim measures a volleyball net to be 82 inches, but its actual height is 92 inches. This problem involves basic arithmetic and the formula for percent error. Suitable for students in Grades 6-8.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation