Violet measured a line to be 1.9 inches long. If the actual length of the line is 2 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?

To find the percent error of Violet's measurement, we can use the formula:

\[
\text{Percent Error} = \left(\frac{\left|\text{Measured Value} - \text{Actual Value}\right|}{\text{Actual Value}}\right) \times 100
\]

In this case:

- Measured Value = 1.9 inches
- Actual Value = 2 inches

Now, let's calculate it:

\[
\text{Percent Error} = \left(\frac{|1.9 - 2|}{2}\right) \times 100 = \left(\frac{0.1}{2}\right) \times 100 = 0.05 \times 100 = 5\%
\]

So, the percent error of the measurement is **5.0%**.

Would you like more details or have any questions?

Here are 5 related questions:
1. How would the percent error change if the measured length was 1.8 inches?
2. What is the significance of percent error in measurements?
3. How can you reduce the percent error in future measurements?
4. What is the difference between percent error and absolute error?
5. How would you calculate percent error if the actual length was unknown?

**Tip:** Always double-check your measurements and calculations to ensure accuracy and reduce errors.

Learn how to calculate percent error in measurements using a detailed example. Find out the percent error when Violet measured a line to be 1.9 inches instead of the actual 2 inches, with step-by-step calculation. Suitable for students in Grades 7-9.

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