20$per month plus$3per mile but charges $5per mile

It sounds like you're describing a scenario where there is a monthly base fee and a per-mile rate for charges, but there's a different rate being applied. Let's break it down:

### Scenario:
- **Monthly base fee**: $20
- **Advertised cost per mile**: $3 per mile
- **Actual cost per mile**: $5 per mile

### Charges Breakdown:
1. **Monthly cost (fixed)**: $20
2. **Variable cost per mile**: Instead of being charged $3 per mile, you are charged $5 per mile.

### Formula:
The total cost $ C $ based on the number of miles $ m $ driven would be:
\[
C = 20 + 5m
\]
Where:
- 20 is the monthly base fee
- $ 5m $ is the actual charge per mile driven

If you want to calculate the cost for a specific number of miles, you can substitute $ m $ with the number of miles driven.

Do you want to go into details or have any questions?

### Relative Questions:
1. How many miles are driven on average per month?
2. Is the $3 per mile a promotional rate, or was it just incorrectly applied?
3. Do you have examples of how much you've been charged based on these rates?
4. Are there any extra fees beyond the $5 per mile?
5. What would the total cost be if you drove 50 miles in one month?

### Tip:
When calculating costs based on mileage, always check for discrepancies between advertised rates and actual charges.

Explore how to calculate the total cost for a monthly base fee of $20 and a per-mile charge of $5. This problem involves key algebraic concepts such as linear equations and cost breakdowns. Suitable for students in Grades 6-8, with an example formula to calculate the total cost for a specific number of miles driven.

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