Math Problem Statement

Suppose T is a linear transformation from R ^ 2 to p_{2} such that RBT: U CO:CO1 Marks: 8 ii) 7 * [[1], [1]] = 2 - 3x + x ^ 2 and r * [[2], [3]] = 1 - x ^ 2 T * [[1], [- 2]] r * [[a], [b]]

Solution

Let's break this down step by step. You're dealing with a linear transformation TT from R2\mathbb{R}^2 to P2P_2, where P2P_2 is the space of polynomials of degree at most 2. The transformation acts on vectors in R2\mathbb{R}^2, and the images of specific vectors under TT are given as polynomials in P2P_2.

Key Information Given:

  1. T([1,1]T)=23x+x2T( [1, 1]^T ) = 2 - 3x + x^2
  2. T([2,3]T)=1x2T( [2, 3]^T ) = 1 - x^2
  3. Find T([1,2]T)T( [1, -2]^T ).

1. Linear Transformation Definition:

Since TT is a linear transformation, we know that for any vectors u,vR2u, v \in \mathbb{R}^2 and scalars a,ba, b, the transformation satisfies:

T(au+bv)=aT(u)+bT(v)T(a \mathbf{u} + b \mathbf{v}) = a T(\mathbf{u}) + b T(\mathbf{v})

We'll use this property to find T([1,2]T)T( [1, -2]^T ).

2. Construct the Solution Using Given Information:

You are given the images of two specific vectors under TT:

T([1,1]T)=23x+x2T( [1, 1]^T ) = 2 - 3x + x^2 T([2,3]T)=1x2T( [2, 3]^T ) = 1 - x^2

Now, we need to express [1,2]T[1, -2]^T as a linear combination of [1,1]T[1, 1]^T and [2,3]T[2, 3]^T.

Let's solve the system:

[ [1, -2]^T = a[1, 1]^T + b[2, 3]^T ]

This leads to the equations: 1=a+2b1 = a + 2b 2=a+3b-2 = a + 3b

3. Solve the System of Equations:

We now have the system:

1 &= a + 2b \\ -2 &= a + 3b \end{aligned}$$ Subtract the first equation from the second: $$(-2 - 1) = (a + 3b) - (a + 2b)$$ $$-3 = b$$ Substitute $$b = -3$$ into the first equation: $$1 = a + 2(-3)$$ $$1 = a - 6$$ $$a = 7$$ So, we have: \[ [1, -2]^T = 7[1, 1]^T - 3[2, 3]^T \] ### 4. Apply the Linear Transformation: Using the linearity of $$T$$, we can now compute $$T( [1, -2]^T )$$: \[ T( [1, -2]^T ) = 7T( [1, 1]^T ) - 3T( [2, 3]^T ) \] Substitute the given values for $$T( [1, 1]^T )$$ and $$T( [2, 3]^T )$$: $$T( [1, -2]^T ) = 7(2 - 3x + x^2) - 3(1 - x^2)$$ Now, distribute the constants: $$T( [1, -2]^T ) = 14 - 21x + 7x^2 - 3 + 3x^2$$ Simplify: $$T( [1, -2]^T ) = (14 - 3) + (-21x) + (7x^2 + 3x^2)$$ $$T( [1, -2]^T ) = 11 - 21x + 10x^2$$ ### Final Answer: $$T( [1, -2]^T ) = 11 - 21x + 10x^2$$ --- Would you like more details on any specific step? Here are some related questions to consider: 1. How do you find the matrix representation of a linear transformation? 2. How do linear transformations between vector spaces work in higher dimensions? 3. Can you always express a vector as a linear combination of other vectors? 4. What are some examples of linear transformations from $$\mathbb{R}^2$$ to $$P_2$$? 5. How does linearity simplify the process of finding images of vectors under a transformation? **Tip**: Always check if you can express a vector as a combination of known vectors to simplify the computation of transformations.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Linear Transformations
Vector Spaces
Polynomials of Degree 2

Formulas

T(a*u + b*v) = a*T(u) + b*T(v)
System of linear equations to find linear combination coefficients

Theorems

Linearity of Linear Transformations
Basis and Dimension Theorem

Suitable Grade Level

Undergraduate Linear Algebra