Math Problem Statement

The table below gives the list price and the number of bids received for five randomly selected items sold through online auctions. Using this data, consider the equation of the regression line, yˆ=b0+b1x , for predicting the number of bids an item will receive based on the list price. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, in practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant.

Price in Dollars 29 33 34 36 46 Number of Bids 1 3 8 9 10 Table

Step 2 of 6 : Find the estimated y-intercept. Round your answer to three decimal places.

Solution

To find the estimated y-intercept b0b_0 for the regression line y^=b0+b1x\hat{y} = b_0 + b_1x, we first need to compute the slope b1b_1 and use the formula for the y-intercept:

b0=yˉb1xˉb_0 = \bar{y} - b_1 \bar{x}

Where:

  • yˉ\bar{y} is the mean of the number of bids.
  • xˉ\bar{x} is the mean of the list prices.
  • b1b_1 is the slope of the regression line, which is calculated as:

b1=(xixˉ)(yiyˉ)(xixˉ)2b_1 = \frac{\sum (x_i - \bar{x})(y_i - \bar{y})}{\sum (x_i - \bar{x})^2}

Step 1: Compute the means

We have the following data:

List prices (xx): 29, 33, 34, 36, 46
Number of bids (yy): 1, 3, 8, 9, 10

First, let's calculate the means of xx and yy.

xˉ=29+33+34+36+465=1785=35.6\bar{x} = \frac{29 + 33 + 34 + 36 + 46}{5} = \frac{178}{5} = 35.6 yˉ=1+3+8+9+105=315=6.2\bar{y} = \frac{1 + 3 + 8 + 9 + 10}{5} = \frac{31}{5} = 6.2

Step 2: Calculate b1b_1

Now, we calculate the numerator and denominator for the slope b1b_1.

  1. Compute the deviations (xixˉ)(x_i - \bar{x}) and (yiyˉ)(y_i - \bar{y}), and their products:
xix_iyiy_ixixˉx_i - \bar{x}yiyˉy_i - \bar{y}(xixˉ)(yiyˉ)(x_i - \bar{x})(y_i - \bar{y})(xixˉ)2(x_i - \bar{x})^2
291-6.6-5.234.3243.56
333-2.6-3.28.326.76
348-1.61.8-2.882.56
3690.42.81.120.16
461010.43.839.52108.16

Now sum the columns for (xixˉ)(yiyˉ)(x_i - \bar{x})(y_i - \bar{y}) and (xixˉ)2(x_i - \bar{x})^2:

(xixˉ)(yiyˉ)=34.32+8.322.88+1.12+39.52=80.4\sum (x_i - \bar{x})(y_i - \bar{y}) = 34.32 + 8.32 - 2.88 + 1.12 + 39.52 = 80.4

(xixˉ)2=43.56+6.76+2.56+0.16+108.16=161.2\sum (x_i - \bar{x})^2 = 43.56 + 6.76 + 2.56 + 0.16 + 108.16 = 161.2

Now, calculate the slope b1b_1:

b1=80.4161.20.499b_1 = \frac{80.4}{161.2} \approx 0.499

Step 3: Calculate the y-intercept b0b_0

Finally, use the formula for b0b_0:

b0=yˉb1xˉ=6.2(0.499)(35.6)=6.217.74=11.54b_0 = \bar{y} - b_1 \bar{x} = 6.2 - (0.499)(35.6) = 6.2 - 17.74 = -11.54

Final Answer

The estimated y-intercept b0b_0 is approximately -11.540.

Would you like to proceed with more details, or do you have any further questions on this? Here are some related questions to deepen the understanding:

  1. How would you compute the slope and intercept for a larger dataset?
  2. What is the interpretation of the regression equation in this context?
  3. How do you test the significance of the correlation coefficient?
  4. What would happen if the correlation coefficient were zero?
  5. How can residuals help assess the quality of the regression model?

Tip: Always check the assumptions of linear regression (linearity, independence, homoscedasticity, and normality of residuals) before making predictions.

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Math Problem Analysis

Mathematical Concepts

Linear Regression
Statistics
Correlation
Slope and Intercept

Formulas

Regression Line Formula: yˆ = b0 + b1x
Slope Formula: b1 = Σ(xi - x̄)(yi - ȳ) / Σ(xi - x̄)²
Y-Intercept Formula: b0 = ȳ - b1x̄

Theorems

Least Squares Method
Linear Regression Analysis

Suitable Grade Level

Grades 10-12