Math Problem Statement

The table below gives the list price and the number of bids received for five randomly selected items sold through online auctions. Using this data, consider the equation of the regression line, yˆ=b0+b1x , for predicting the number of bids an item will receive based on the list price. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, in practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant.

Price in Dollars 21 26 28 35 43 Number of Bids 1 3 5 6 9 Table

Step 2 of 6 : Find the estimated y-intercept. Round your answer to three decimal places.

Solution

To find the estimated y-intercept (b0b_0) of the regression line equation y^=b0+b1x\hat{y} = b_0 + b_1 x, we need to first compute the slope (b1b_1) and then use the formula to find b0b_0.

The formula for the slope (b1b_1) is:

b1=nxyxynx2(x)2b_1 = \frac{n \sum{x y} - \sum{x} \sum{y}}{n \sum{x^2} - (\sum{x})^2}

And once we have b1b_1, the y-intercept b0b_0 can be calculated using the following formula:

b0=yb1xnb_0 = \frac{\sum{y} - b_1 \sum{x}}{n}

Where:

  • xx represents the list price,
  • yy represents the number of bids,
  • nn is the number of data points (in this case, n=5n = 5).

Step 1: Calculate the necessary sums

We are given the following data:

Price (x)Number of Bids (y)
211
263
285
356
439

Now, let's compute the necessary sums:

  • x=21+26+28+35+43=153\sum{x} = 21 + 26 + 28 + 35 + 43 = 153
  • y=1+3+5+6+9=24\sum{y} = 1 + 3 + 5 + 6 + 9 = 24
  • xy=(21×1)+(26×3)+(28×5)+(35×6)+(43×9)\sum{xy} = (21 \times 1) + (26 \times 3) + (28 \times 5) + (35 \times 6) + (43 \times 9)
  • x2=(212)+(262)+(282)+(352)+(432)\sum{x^2} = (21^2) + (26^2) + (28^2) + (35^2) + (43^2)

Let's calculate each of these:

xy=(21×1)+(26×3)+(28×5)+(35×6)+(43×9)=21+78+140+210+387=836\sum{xy} = (21 \times 1) + (26 \times 3) + (28 \times 5) + (35 \times 6) + (43 \times 9) = 21 + 78 + 140 + 210 + 387 = 836

x2=(212)+(262)+(282)+(352)+(432)=441+676+784+1225+1849=4975\sum{x^2} = (21^2) + (26^2) + (28^2) + (35^2) + (43^2) = 441 + 676 + 784 + 1225 + 1849 = 4975

Step 2: Compute the slope b1b_1

Now, substitute these sums into the formula for b1b_1:

b1=5×836153×245×4975(153)2b_1 = \frac{5 \times 836 - 153 \times 24}{5 \times 4975 - (153)^2}

b1=418036722487523409b_1 = \frac{4180 - 3672}{24875 - 23409}

b1=508466b_1 = \frac{508}{466}

b11.09b_1 \approx 1.09

Step 3: Compute the y-intercept b0b_0

Now, substitute the values of b1b_1, x\sum{x}, and y\sum{y} into the formula for b0b_0:

b0=241.09×1535b_0 = \frac{24 - 1.09 \times 153}{5}

b0=24166.775b_0 = \frac{24 - 166.77}{5}

b0=142.775b_0 = \frac{-142.77}{5}

b028.554b_0 \approx -28.554

Final Answer:

The estimated y-intercept b0b_0 is approximately -28.554.

Would you like to proceed with further steps to calculate the slope and check for statistical significance? Let me know if you need more details!

Related Questions:

  1. How can you calculate the slope of the regression line using the least squares method?
  2. What does the correlation coefficient tell you about the strength of the relationship between the price and number of bids?
  3. Why might the regression line not be a good predictor if the correlation coefficient is not statistically significant?
  4. How do you interpret the value of the y-intercept in this context?
  5. What would the next steps be to calculate the regression line’s equation fully?

Tip:

Remember, while the y-intercept and slope are important for finding the equation of the regression line, the significance of these values depends on the statistical analysis, such as calculating the p-value of the correlation coefficient!

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Math Problem Analysis

Mathematical Concepts

Linear Regression
Correlation Coefficient
Statistics

Formulas

ŷ = b0 + b1x
b1 = (n * Σxy - Σx * Σy) / (n * Σx² - (Σx)²)
b0 = (Σy - b1 * Σx) / n

Theorems

Least Squares Method

Suitable Grade Level

Grades 10-12