Math Problem Statement

Construct the inverse function for g(x) = 6^(x + 8).

Solution

The image shows a multiple-choice question asking for the inverse function of g(x)=6(x+8)g(x) = 6^{(x + 8)}.

To find the inverse of a function like this, follow these steps:

Steps to find the inverse:

  1. Write the equation for g(x)g(x): g(x)=6(x+8)g(x) = 6^{(x + 8)}

  2. Replace g(x)g(x) with yy: y=6(x+8)y = 6^{(x + 8)}

  3. Solve for xx in terms of yy: To do this, take the logarithm (base 6) of both sides: log6(y)=x+8\log_6(y) = x + 8

  4. Solve for xx: x=log6(y)8x = \log_6(y) - 8

  5. Replace yy with xx to get the inverse function: g1(x)=log6(x)8g^{-1}(x) = \log_6(x) - 8

Conclusion:

The correct inverse function is: g1(x)=log6(x)8g^{-1}(x) = \log_6(x) - 8

Looking at your options, the second one matches this result: g1(x)=log6(x)8g^{-1}(x) = \log_6(x) - 8

Do you need any further clarifications or details?

Here are 5 related questions you might find interesting:

  1. How do we handle logarithms with different bases when solving for an inverse?
  2. How can I verify if two functions are indeed inverses of each other?
  3. What happens to the domain and range when you find the inverse of a function?
  4. How do exponential functions behave when reversed by logarithms?
  5. Can inverse functions always be represented in a closed form?

Tip: When working with logarithmic functions, remember the basic property: logb(a)=c\log_b(a) = c means bc=ab^c = a.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Inverse Functions
Exponential Functions
Logarithms

Formulas

y = b^(x) implies log_b(y) = x
Inverse function: solve for x in terms of y

Theorems

Inverse Function Theorem
Properties of Logarithms

Suitable Grade Level

Grades 10-12