Math Problem Statement

Given that AB = BC and DE = CD, prove that AC = BD using segment addition and substitution.

Solution

The image you uploaded contains a geometric proof with a two-column format: one side for "Statements" and the other for "Reasons." The goal is to prove that segment AC = BD given the statements:

Given:

  • AB=BCAB = BC
  • DE=CDDE = CD

Proof Layout:

StatementReason
1. AB=BCAB = BC, DE=CDDE = CDGiven
2. AC=AB+BCAC = AB + BC, BD=BC+CDBD = BC + CDSegment Addition
3. AC=BDAC = BDSubstitution

Explanation:

  1. Statement 1: AB=BCAB = BC and DE=CDDE = CD are provided as the given information.
  2. Statement 2: Applying the segment addition postulate, we express the lengths of ACAC and BDBD as sums of segments. Specifically:
    • AC=AB+BCAC = AB + BC
    • BD=BC+CDBD = BC + CD
  3. Statement 3: Using the given information, we substitute the equalities into the second statement. Since AB=BCAB = BC and CD=DECD = DE, we conclude that AC=BDAC = BD.

Would you like any further details or a more in-depth explanation?

Here are 5 related questions to help expand your understanding:

  1. How does the segment addition postulate work in this proof?
  2. What role do the given equalities AB=BCAB = BC and DE=CDDE = CD play in reaching the conclusion?
  3. Can this proof be applied to other types of geometric figures?
  4. What is the importance of substitution in mathematical proofs?
  5. How would you write the converse of this proof?

Tip: When working through geometric proofs, always ensure you understand each postulate or theorem being applied—this helps clarify the logic behind each step.

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Math Problem Analysis

Mathematical Concepts

Geometry
Segment Addition

Formulas

AC = AB + BC
BD = BC + CD

Theorems

Segment Addition Postulate
Substitution

Suitable Grade Level

Grades 9-10