Math Problem Statement

Given: AB = CD and BC = DE. Prove: AC = CE

Solution

The question asks to convert the given paragraph proof into a two-column proof format. Let's break it down step-by-step and present it in a two-column format.

Given:

  • AB=CDAB = CD
  • BC=DEBC = DE

To Prove:

  • AC=CEAC = CE

Paragraph Proof Explanation:

  • By the addition property of equality, adding BCBC to both sides of AB=CDAB = CD gives AB+BC=CD+BCAB + BC = CD + BC.
  • Given BC=DEBC = DE, we can substitute DEDE for BCBC in the equation, resulting in AB+DE=CD+DEAB + DE = CD + DE.
  • Using segment addition, we observe that AB+BC=ACAB + BC = AC and CD+DE=CECD + DE = CE.
  • Finally, substituting these values, we get AC=CEAC = CE.

Two-Column Proof:

StatementsReasons
1. AB=CDAB = CD1. Given
2. BC=DEBC = DE2. Given
3. AB+BC=CD+BCAB + BC = CD + BC3. Addition Property of Equality
4. AB+DE=CD+DEAB + DE = CD + DE4. Substitution Property of Equality
5. AB+BC=ACAB + BC = AC5. Segment Addition Postulate
6. CD+DE=CECD + DE = CE6. Segment Addition Postulate
7. AC=CEAC = CE7. Substitution Property of Equality

This proof structure is more formal and clear, adhering to the standard two-column proof method.

Would you like more details on the steps, or do you have any questions?

Here are 5 related questions:

  1. Can you explain the Addition Property of Equality?
  2. What is the Segment Addition Postulate?
  3. How does the Substitution Property of Equality work in proofs?
  4. Why is it important to have clear reasoning in a two-column proof?
  5. How can this proof be applied to other geometric problems?

Tip: In geometry, always make sure to clearly state all given information and identify what needs to be proven before starting your proof.

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Math Problem Analysis

Mathematical Concepts

Geometry
Proofs
Equality Properties

Formulas

Addition Property of Equality
Segment Addition Postulate

Theorems

Substitution Property of Equality
Addition Property of Equality
Segment Addition Postulate

Suitable Grade Level

Grade 9-10