Math Problem Statement

For f(x) = x2 + 12 and g(x) = √3x + 2, find 𝑓 ∘ 𝑔

Solution

To find (fg)(x)(f \circ g)(x), we substitute g(x)g(x) into f(x)f(x):

Given functions:

  • f(x)=x2+12f(x) = x^2 + 12
  • g(x)=3x+2g(x) = \sqrt{3x + 2}

Compute (fg)(x)(f \circ g)(x):

(fg)(x)=f(g(x))=f(3x+2)(f \circ g)(x) = f(g(x)) = f(\sqrt{3x + 2}) Since f(x)=x2+12f(x) = x^2 + 12, replacing xx with g(x)g(x):

f(g(x))=(3x+2)2+12f(g(x)) = (\sqrt{3x + 2})^2 + 12

=(3x+2)+12= (3x + 2) + 12

=3x+14= 3x + 14

Final Answer:

(fg)(x)=3x+14(f \circ g)(x) = 3x + 14

Would you like a more detailed explanation or an example?

Related Questions:

  1. How do you find (gf)(x)(g \circ f)(x)?
  2. What is the domain of (fg)(x)(f \circ g)(x)?
  3. How do composition functions relate to inverse functions?
  4. Can function composition be commutative?
  5. How do you verify if a function composition is valid?

Tip:

Always check the domain restrictions when composing functions, as some inputs might be undefined in the inner function!

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Math Problem Analysis

Mathematical Concepts

Function Composition
Algebra
Square Roots

Formulas

f(x) = x^2 + 12
g(x) = √(3x + 2)
(f ∘ g)(x) = f(g(x))

Theorems

Function Composition Theorem

Suitable Grade Level

Grades 9-11