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To solve \( f(g(4)) \) based on the given functions:

- \( f(x) = \sqrt{x + 1} \)
- \( g(x) = 2x - 5 \)

We need to:

1. First, evaluate \( g(4) \):
   \[
   g(4) = 2(4) - 5 = 8 - 5 = 3
   \]

2. Now, use this result to evaluate \( f(g(4)) = f(3) \):
   \[
   f(3) = \sqrt{3 + 1} = \sqrt{4} = 2
   \]

Thus, \( f(g(4)) = 2 \).

Would you like more details or further clarification?

Here are 5 related questions for practice:

1. What is \( f(g(2)) \) with the same functions?
2. If \( h(x) = 3x^2 - 3 \), what is \( h(g(4)) \)?
3. Can you find the inverse of \( f(x) = \sqrt{x+1} \)?
4. What is \( f(f(4)) \) for the same \( f(x) \)?
5. How does the composition of two functions work in general?

**Tip:** Always solve the inner function first when evaluating a composition of functions!

Let f(x) = √(x + 1), g(x) = 2x - 5, and h(x) = 3x^2 - 3. Find the indicated value f(g(4)).

Learn how to solve the composition of two functions, f(x) = √(x + 1) and g(x) = 2x - 5, to find f(g(4)). This step-by-step solution demonstrates key algebraic concepts such as function composition and square root calculations. Suitable for Grades 9-10.

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