To solve $f(g(4))$ based on the given functions:

• $f(x) = \sqrt{x + 1}$
• $g(x) = 2x - 5$

We need to:

1. First, evaluate $g(4)$: $g(4) = 2(4) - 5 = 8 - 5 = 3$

2. Now, use this result to evaluate $f(g(4)) = f(3)$: $f(3) = \sqrt{3 + 1} = \sqrt{4} = 2$

Thus, $f(g(4)) = 2$.

Would you like more details or further clarification?

Here are 5 related questions for practice:

1. What is $f(g(2))$ with the same functions?
2. If $h(x) = 3x^2 - 3$, what is $h(g(4))$?
3. Can you find the inverse of $f(x) = \sqrt{x+1}$?
4. What is $f(f(4))$ for the same $f(x)$?
5. How does the composition of two functions work in general?

Tip: Always solve the inner function first when evaluating a composition of functions!