Math Problem Statement

answer

Given f(x) = 5x + 3, g(x) = x^2 - 7, and h(x) = x + 5, find the value of (f ∘ (g ∘ h))(x).

Solution

Let's analyze the problem from the image you uploaded.

Given Functions:

  1. f(x)=5x+3f(x) = 5x + 3
  2. g(x)=x27g(x) = x^2 - 7
  3. h(x)=x+5h(x) = x + 5

We are asked to find the composition of functions fghf \circ g \circ h, which means we first find g(h(x))g(h(x)) and then apply ff to the result.

Step-by-Step Solution:

  1. Find g(h(x))g(h(x)): h(x)=x+5h(x) = x + 5 Substitute h(x)h(x) into g(x)g(x): g(h(x))=g(x+5)=(x+5)27g(h(x)) = g(x+5) = (x+5)^2 - 7 Expanding (x+5)2(x+5)^2: (x+5)2=x2+10x+25(x+5)^2 = x^2 + 10x + 25 So, g(h(x))=x2+10x+257=x2+10x+18g(h(x)) = x^2 + 10x + 25 - 7 = x^2 + 10x + 18

  2. Find f(g(h(x)))f(g(h(x))): Now substitute g(h(x))=x2+10x+18g(h(x)) = x^2 + 10x + 18 into f(x)f(x): f(g(h(x)))=f(x2+10x+18)=5(x2+10x+18)+3f(g(h(x))) = f(x^2 + 10x + 18) = 5(x^2 + 10x + 18) + 3 Distribute the 5: f(g(h(x)))=5x2+50x+90+3=5x2+50x+93f(g(h(x))) = 5x^2 + 50x + 90 + 3 = 5x^2 + 50x + 93

Thus, f(g(h(x)))=5x2+50x+93f(g(h(x))) = 5x^2 + 50x + 93.

However, looking at the choices from the image, the correct answer should be Option C: 5x250x+835x^2 - 50x + 83, which seems different. Double-checking your selections or reviewing the steps again could help clarify the correct calculation.

Would you like more details or clarification on this?

Relative Questions:

  1. How do you calculate function composition step by step?
  2. Can function composition be done for more than two functions?
  3. What is the significance of expanding polynomials when composing functions?
  4. How can errors in sign or arithmetic be avoided in function composition?
  5. Can function composition be applied to real-world scenarios?

Tip:

Always verify the operations (addition, multiplication, etc.) when composing functions to avoid small mistakes.

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Math Problem Analysis

Mathematical Concepts

Function Composition
Quadratic Expansion

Formulas

f(x) = 5x + 3
g(x) = x^2 - 7
h(x) = x + 5

Theorems

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Suitable Grade Level

Grades 9-12