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To solve this problem, we first need to understand the relationship between the perimeter and the area of a square.

### Step 1: Perimeter of a square
The formula for the perimeter \( P \) of a square is:
\[
P = 4 \times s
\]
where \( s \) is the length of one side of the square.

We are given that the perimeter is 12 feet. So,
\[
12 = 4 \times s
\]
Solving for \( s \), we get:
\[
s = \frac{12}{4} = 3 \text{ feet}
\]

### Step 2: Area of a square
The formula for the area \( A \) of a square is:
\[
A = s^2
\]
Since \( s = 3 \) feet, the area is:
\[
A = 3^2 = 9 \text{ square feet}
\]

Thus, the area of the square table is **9 square feet**.

Would you like further details or have any questions?

Here are 5 related questions to consider:
1. What would the area be if the perimeter were 16 feet?
2. How does the area change if the side length is doubled?
3. What is the formula for the diagonal of a square, and how long is the diagonal for this table?
4. If the table were rectangular with the same perimeter, would its area be larger or smaller?
5. What is the area of a square with a side length of 5 feet?

**Tip:** The area of a square increases quadratically as the side length increases, meaning small changes in the side length have a big impact on the area.

If a square table has a perimeter (the distance around) of 12 feet, what is the area of that table?

Learn how to find the area of a square table with a given perimeter of 12 feet. This geometry problem involves understanding the relationship between perimeter and area using the formulas P = 4 * s and A = s^2. Suitable for Grades 6-8.

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