Math Problem Statement

Value of w?

Solution

Given that the total number of students NN is 125, we can use the relative frequencies and the total number of students to find the value of ww (the number of students who bike).

First, let's understand the known relative frequency for walking: Relative frequency for walking=25125=0.2\text{Relative frequency for walking} = \frac{25}{125} = 0.2

The sum of all relative frequencies should be 1. Therefore, we need to express the relative frequency of biking in terms of ww:

Relative frequency for biking=w125\text{Relative frequency for biking} = \frac{w}{125}

Let's denote the unknown relative frequencies for public transport, car, and cycle as rfPT,rfcar,rf_{\text{PT}}, rf_{\text{car}}, and rfcyclerf_{\text{cycle}} respectively. So we have:

rfPT+rfcar+rfcycle+w125+0.2=1rf_{\text{PT}} + rf_{\text{car}} + rf_{\text{cycle}} + \frac{w}{125} + 0.2 = 1

Since we don't have the relative frequencies for public transport, car, and cycle, we will use the sum of all relative frequencies to isolate ww:

rfPT+rfcar+rfcycle+w125+0.2=1rf_{\text{PT}} + rf_{\text{car}} + rf_{\text{cycle}} + \frac{w}{125} + 0.2 = 1

Rearranging to solve for ww:

rfPT+rfcar+rfcycle+w125=0.8rf_{\text{PT}} + rf_{\text{car}} + rf_{\text{cycle}} + \frac{w}{125} = 0.8

Let's say the sum of relative frequencies for public transport, car, and cycle is SS: S+w125=0.8S + \frac{w}{125} = 0.8

Since SS is unknown, we'll use the sum of the frequencies to isolate ww:

w125=0.8S\frac{w}{125} = 0.8 - S

To find ww: w=125(0.8S)w = 125(0.8 - S)

We need the actual relative frequencies for public transport, car, and cycle to determine SS and subsequently ww. Assuming no additional information is given, the exact value of ww cannot be found without knowing the sum SS. If we assume SS is 0, then:

w=125(0.80)w = 125(0.8 - 0) w=100w = 100

Thus, the value of ww would be 100 if there are no other students using public transport, car, or cycle. If you have the relative frequencies for public transport, car, or cycle, we can refine this calculation.

Would you like more details or have any questions?

Here are 5 questions you can ask:

  1. How do you find the relative frequencies for public transport, car, and cycle?
  2. How can we verify the consistency of relative frequencies in the table?
  3. Can you explain the calculation of relative frequency in more detail?
  4. What if the relative frequencies for public transport, car, and cycle are given? How would ww change?
  5. How can we use relative frequency to analyze other similar problems?

Tip: When solving problems involving relative frequencies, ensure all given values add up correctly to maintain the balance of the total sum.