Without actually solving the​ problem, choose the correct solution by deciding which choice satisfies the given conditions.
The length of a rectangle is 3 feet longer than the width. The perimeter is 18 feet. Find the dimensions of the rectangle.

Given that the length of the rectangle is 3 feet longer than the width, and the perimeter is 18 feet, let's determine which choice satisfies these conditions.

Let:
- The width of the rectangle be \( w \).
- The length of the rectangle be \( w + 3 \).

The perimeter of a rectangle is given by the formula:
\[
P = 2(\text{length} + \text{width})
\]
Substituting the expressions for length and width:
\[
18 = 2((w + 3) + w)
\]

Now, we simplify the equation:
\[
18 = 2(2w + 3)
\]
\[
18 = 4w + 6
\]
Subtracting 6 from both sides:
\[
12 = 4w
\]
Dividing both sides by 4:
\[
w = 3
\]

Thus, the width is 3 feet, and the length is \( w + 3 = 6 \) feet.

### The correct dimensions of the rectangle are: 
- Width = 3 feet
- Length = 6 feet.

Would you like me to provide more details or answer any questions?

### Relative Questions:
1. How would the dimensions change if the perimeter was increased to 24 feet?
2. What happens to the dimensions if the length is 5 feet longer than the width?
3. How can we apply this method to other shapes with different perimeter formulas?
4. How does the formula for perimeter change if the shape was a square?
5. What would the area of this rectangle be with the given dimensions?

### Tip: 
Always double-check that your values satisfy all conditions of the problem, like ensuring the perimeter equation holds after solving for dimensions.

Discover how to find the dimensions of a rectangle when given its perimeter of 18 feet. This problem involves basic geometry concepts and uses the formula for the perimeter of a rectangle. Suitable for students in Grades 5-7.

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