Math Problem Statement

Find the value of n for which the vector r ^ n * r solenoidal, where r =x hat i +y hat j +z hat k .

Solution

To find the value of nn for which the vector rnr\mathbf{r}^n \cdot \mathbf{r} is solenoidal, where r=xi^+yj^+zk^\mathbf{r} = x \hat{i} + y \hat{j} + z \hat{k}, we need to ensure that the divergence of the vector field is zero. A vector field F\mathbf{F} is solenoidal if F=0\nabla \cdot \mathbf{F} = 0.

Given: r=xi^+yj^+zk^\mathbf{r} = x \hat{i} + y \hat{j} + z \hat{k}

We need to evaluate the divergence of: F=rnr\mathbf{F} = r^n \mathbf{r}

Where r=x2+y2+z2r = \sqrt{x^2 + y^2 + z^2}.

So, F=rn(xi^+yj^+zk^)=xrni^+yrnj^+zrnk^\mathbf{F} = r^n (x \hat{i} + y \hat{j} + z \hat{k}) = x r^n \hat{i} + y r^n \hat{j} + z r^n \hat{k}

To find the divergence, we calculate: F=x(xrn)+y(yrn)+z(zrn)\nabla \cdot \mathbf{F} = \frac{\partial}{\partial x} (x r^n) + \frac{\partial}{\partial y} (y r^n) + \frac{\partial}{\partial z} (z r^n)

Each term involves the product rule for differentiation: x(xrn)=rn+xx(rn)\frac{\partial}{\partial x} (x r^n) = r^n + x \frac{\partial}{\partial x} (r^n)

Using the chain rule: x(rn)=nrn1rx=nrn1xr=nxrn2\frac{\partial}{\partial x} (r^n) = n r^{n-1} \frac{\partial r}{\partial x} = n r^{n-1} \frac{x}{r} = n x r^{n-2}

Thus, x(xrn)=rn+xnxrn2=rn+nx2rn2\frac{\partial}{\partial x} (x r^n) = r^n + x \cdot n x r^{n-2} = r^n + n x^2 r^{n-2}

Similarly: y(yrn)=rn+ny2rn2\frac{\partial}{\partial y} (y r^n) = r^n + n y^2 r^{n-2} z(zrn)=rn+nz2rn2\frac{\partial}{\partial z} (z r^n) = r^n + n z^2 r^{n-2}

Summing these partial derivatives: F=(rn+nx2rn2)+(rn+ny2rn2)+(rn+nz2rn2)\nabla \cdot \mathbf{F} = (r^n + n x^2 r^{n-2}) + (r^n + n y^2 r^{n-2}) + (r^n + n z^2 r^{n-2}) F=3rn+n(x2+y2+z2)rn2\nabla \cdot \mathbf{F} = 3r^n + n (x^2 + y^2 + z^2) r^{n-2}

Since r2=x2+y2+z2r^2 = x^2 + y^2 + z^2, we can substitute: F=3rn+nr2rn2\nabla \cdot \mathbf{F} = 3r^n + n r^2 r^{n-2} F=3rn+nrn\nabla \cdot \mathbf{F} = 3r^n + n r^n F=(3+n)rn\nabla \cdot \mathbf{F} = (3 + n) r^n

For the vector field to be solenoidal, the divergence must be zero: (3+n)rn=0(3 + n) r^n = 0

Since rn0r^n \neq 0 for any non-zero r\mathbf{r}, we have: 3+n=03 + n = 0 n=3n = -3

Therefore, the value of nn for which the vector field rnr\mathbf{r}^n \cdot \mathbf{r} is solenoidal is n=3n = -3.

Do you want more details or have any questions?

Here are some related questions to explore:

  1. What is the definition of a solenoidal vector field?
  2. How do you compute the divergence of a vector field in Cartesian coordinates?
  3. What is the physical significance of a solenoidal vector field?
  4. How would the solution change if we considered a different coordinate system, like spherical coordinates?
  5. Can you derive the expression for the gradient of a scalar field?
  6. What is the curl of a vector field and how is it related to solenoidal fields?
  7. How can we apply the concept of solenoidal fields in fluid dynamics?
  8. What are some real-world examples of solenoidal vector fields?

Tip: When dealing with vector calculus, always remember to use the appropriate coordinate system for simplifying your calculations.

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Math Problem Analysis

Mathematical Concepts

Vector calculus
Divergence theorem

Formulas

Divergence of a vector field in Cartesian coordinates

Theorems

Solenoidal vector fields

Suitable Grade Level

Advanced undergraduate level