Math Problem Statement

esthetic

Quadrilateral JKLM is similar to quadrilateral NOPQ. Find the measure of side QN. Round your answer to the nearest tenth if necessary.

Solution

To solve this problem, let's examine the given information and apply properties of similar quadrilaterals.

  1. Given:

    • Quadrilateral JKLMJKLM is similar to quadrilateral NOPQNOPQ.
    • Side JK=8JK = 8 in JKLMJKLM corresponds to side NO=39NO = 39 in NOPQNOPQ.
    • Side JM=13JM = 13 in JKLMJKLM corresponds to side QNQN in NOPQNOPQ, which we need to find.
  2. Similarity Ratio: Since the quadrilaterals are similar, the ratios of corresponding sides are equal. Therefore, we can set up a proportion based on the sides we know: JKNO=JMQN\frac{JK}{NO} = \frac{JM}{QN} Substituting the known values: 839=13QN\frac{8}{39} = \frac{13}{QN}

  3. Solving for QNQN: Cross-multiplying to solve for QNQN: 8QN=13398 \cdot QN = 13 \cdot 39 8QN=5078 \cdot QN = 507 QN=5078=63.375QN = \frac{507}{8} = 63.375

  4. Rounding: Rounding 63.37563.375 to the nearest tenth, we get: QN63.4QN \approx 63.4

Answer: The measure of side QNQN is approximately 63.4.

Would you like more details or have any questions?


Here are some related questions to deepen understanding:

  1. How does the similarity of polygons help in solving problems with unknown side lengths?
  2. What are the other properties that are preserved in similar polygons besides side ratios?
  3. How can we determine if two polygons are similar just by looking at side ratios?
  4. What would change in the solution if a different pair of corresponding sides were used?
  5. How can this concept of similarity be applied to triangles specifically?

Tip: When dealing with similar shapes, always confirm that corresponding sides are matched correctly to ensure accurate calculations.

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Math Problem Analysis

Mathematical Concepts

Geometry
Similarity of Quadrilaterals
Ratios and Proportions

Formulas

\( \frac{JK}{NO} = \frac{JM}{QN} \)

Theorems

Similarity of polygons theorem

Suitable Grade Level

Grades 8-10