Math Problem Statement

let 

a⃗ =2i^−j^+2k^a→=2i^−j^+2k^

 , then find 

a⃗ |a⃗ |

Solution

Given the vector a=2i^j^+2k^\vec{a} = 2\hat{i} - \hat{j} + 2\hat{k}, we are tasked with finding the normalized vector, which is denoted as aa\frac{\vec{a}}{|\vec{a}|}.

Steps:

  1. Find the magnitude of vector a\vec{a}:

The magnitude of a\vec{a} is given by: a=(2)2+(1)2+(2)2=4+1+4=9=3|\vec{a}| = \sqrt{(2)^2 + (-1)^2 + (2)^2} = \sqrt{4 + 1 + 4} = \sqrt{9} = 3

  1. Normalize the vector a\vec{a}:

To find the normalized vector aa\frac{\vec{a}}{|\vec{a}|}, divide each component of a\vec{a} by its magnitude: aa=13(2i^j^+2k^)\frac{\vec{a}}{|\vec{a}|} = \frac{1}{3}(2\hat{i} - \hat{j} + 2\hat{k})

Thus, the normalized vector is: aa=23i^13j^+23k^\frac{\vec{a}}{|\vec{a}|} = \frac{2}{3}\hat{i} - \frac{1}{3}\hat{j} + \frac{2}{3}\hat{k}

Final Answer:

aa=23i^13j^+23k^\frac{\vec{a}}{|\vec{a}|} = \frac{2}{3}\hat{i} - \frac{1}{3}\hat{j} + \frac{2}{3}\hat{k}

Would you like further details or have any questions?

Related Questions:

  1. What is the significance of normalizing a vector?
  2. How do you find the direction cosines of a vector?
  3. What are unit vectors and how are they used in physics?
  4. How do vector operations like dot product and cross product differ?
  5. How does the magnitude of a vector affect its physical meaning in applications?

Tip: Always check your vector's magnitude before normalizing to ensure the resulting unit vector is correct.

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Math Problem Analysis

Mathematical Concepts

Vectors
Magnitude
Normalization

Formulas

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Theorems

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Suitable Grade Level

Grades 10-12