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The problem asks for the equation of a line that is:

- Parallel to the line \( x = -16 \), and
- Passes through the point \( (-8, 2) \).

### Step-by-Step Explanation:

1. **Recognize the given line's form**: 
   The line \( x = -16 \) is a vertical line. Any line parallel to a vertical line will also be a vertical line, meaning its equation will be of the form \( x = c \), where \( c \) is a constant.

2. **Determine the equation of the parallel line**: 
   Since the line we need is parallel to \( x = -16 \) and passes through the point \( (-8, 2) \), the equation of the parallel line must be \( x = -8 \), because the \( x \)-coordinate of the point determines the vertical line.

### Final Answer:
The equation of the parallel line is:
\[
x = -8
\]

Do you have any further questions or would you like more details? 

Here are five related questions for practice:
1. What is the slope of a vertical line?
2. How do you find the equation of a line parallel to another line in slope-intercept form?
3. What is the general form of the equation of a line passing through two points?
4. What is the equation of a line perpendicular to \( x = -16 \) passing through \( (-8, 2) \)?
5. How do you find the distance between two parallel lines?

**Tip**: Remember, vertical lines have undefined slopes, while horizontal lines have a slope of 0.

Find an equation for the line with the given properties: Parallel to the line x = -16 and containing the point (-8, 2).

Learn how to find the equation of a line parallel to x = -16 that passes through the point (-8, 2). This problem explains vertical lines and the concept of parallelism in geometry, suitable for students in Grades 8-10.

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