Math Problem Statement

Find the equation of line (10,5) and (8,3) using two point form equation

Solution

The equation of a line passing through two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) can be written using the two-point form:

yy1=y2y1x2x1(xx1)y - y_1 = \frac{y_2 - y_1}{x_2 - x_1}(x - x_1)

Given Points:

  • (x1,y1)=(10,5)(x_1, y_1) = (10, 5)
  • (x2,y2)=(8,3)(x_2, y_2) = (8, 3)

Step 1: Find the slope (mm):

m=y2y1x2x1=35810=22=1m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 5}{8 - 10} = \frac{-2}{-2} = 1

Step 2: Substitute into the two-point form:

yy1=m(xx1)y - y_1 = m(x - x_1)

Substitute y1=5y_1 = 5, x1=10x_1 = 10, and m=1m = 1: y5=1(x10)y - 5 = 1(x - 10)

Step 3: Simplify:

y5=x10y - 5 = x - 10

y=x5y = x - 5

Final Equation of the Line:

y=x5y = x - 5


Do you want to see more about verifying this result or graphing it? Let me know!


Questions for Further Exploration:

  1. How do you derive the two-point form of a line equation?
  2. Can we convert y=x5y = x - 5 into standard form Ax+By+C=0Ax + By + C = 0?
  3. What would the equation look like if the slope were undefined (vertical line)?
  4. How would the equation change if the points were flipped (e.g., (8,3)(8, 3) first)?
  5. What are the intercepts of the line y=x5y = x - 5?

Tip: Always check the slope calculation carefully when using two-point form; it's a common source of mistakes.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Linear Equations
Slope of a Line

Formulas

Two-Point Form of a Line: y - y1 = ((y2 - y1) / (x2 - x1))(x - x1)
Slope Formula: m = (y2 - y1) / (x2 - x1)

Theorems

Concept of slope and its use in the two-point form equation

Suitable Grade Level

Grades 8-10