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I can help you solve the questions visible in the image! Let's begin with question 1:

### Question 1:
A travels at 50 kmph and reaches his destination at 4 p.m. If he increases his speed to 60 kmph, he reaches one hour earlier. Find the distance he has to travel to reach his destination.

#### Solution:

Let the distance to be traveled be \( d \) kilometers.

- When A travels at 50 km/h, the time taken to reach his destination is \( \frac{d}{50} \) hours.
- When A travels at 60 km/h, the time taken is \( \frac{d}{60} \) hours.

According to the question, the difference in time is 1 hour:

\[
\frac{d}{50} - \frac{d}{60} = 1
\]

We can solve this equation by finding a common denominator for the fractions:

\[
\frac{6d - 5d}{300} = 1 \quad \Rightarrow \quad \frac{d}{300} = 1 \quad \Rightarrow \quad d = 300 \text{ km}
\]

### Answer for Question 1: The distance A has to travel is 300 km.

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Would you like me to solve more questions from the sheet, or do you have any specific queries?

Here are five questions to expand on the current problem:

1. How does changing speed affect the time taken to travel a fixed distance?
2. What are the mathematical principles behind finding time differences in travel problems?
3. How can we set up an equation when dealing with two variables like speed and time?
4. What is the importance of using common denominators when solving fractional equations?
5. Could this type of problem be generalized for any two speeds?

**Tip:** When dealing with time, distance, and speed, remember that \( \text{Time} = \frac{\text{Distance}}{\text{Speed}} \), and rearranging this can help solve many motion-related problems!

A travels at 50 kmph and reaches his destination at 4 p.m. If he increases his speed to 60 kmph, he reaches one hour earlier. Find the distance he has to travel to reach his destination.

Solve a problem where a traveler increases his speed from 50 kmph to 60 kmph, resulting in a 1-hour time difference. This problem involves calculating distance using the speed-distance-time relationship.

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