Math Problem Statement

Find the value(s) of c such that the angle between a = i + cj + 2k and b = -i + 2j - k is 60°.

Solution

The question asks to find the value of cc such that the angle between two vectors a\mathbf{a} and b\mathbf{b} is 60°.

The given vectors are:

a=i+cj+2kandb=i+2jk\mathbf{a} = i + cj + 2k \quad \text{and} \quad \mathbf{b} = -i + 2j - k

We can calculate the angle θ\theta between two vectors using the formula:

cosθ=abab\cos \theta = \frac{\mathbf{a} \cdot \mathbf{b}}{|\mathbf{a}| |\mathbf{b}|}

Where:

  • ab\mathbf{a} \cdot \mathbf{b} is the dot product of vectors a\mathbf{a} and b\mathbf{b},
  • a|\mathbf{a}| and b|\mathbf{b}| are the magnitudes of a\mathbf{a} and b\mathbf{b}, respectively,
  • θ\theta is the angle between the vectors.

Since we are given that the angle between the vectors is 60°, we can substitute cos60=12\cos 60^\circ = \frac{1}{2} into the formula to find cc.

Let's compute the necessary values and solve for cc.

  1. The dot product of a\mathbf{a} and b\mathbf{b}:

ab=(1)(1)+(c)(2)+(2)(1)=1+2c2=2c3\mathbf{a} \cdot \mathbf{b} = (1)(-1) + (c)(2) + (2)(-1) = -1 + 2c - 2 = 2c - 3

  1. The magnitudes of a\mathbf{a} and b\mathbf{b}:

a=12+c2+22=1+c2+4=c2+5|\mathbf{a}| = \sqrt{1^2 + c^2 + 2^2} = \sqrt{1 + c^2 + 4} = \sqrt{c^2 + 5}

b=(1)2+22+(1)2=1+4+1=6|\mathbf{b}| = \sqrt{(-1)^2 + 2^2 + (-1)^2} = \sqrt{1 + 4 + 1} = \sqrt{6}

Now substitute into the equation:

2c3c2+5×6=12\frac{2c - 3}{\sqrt{c^2 + 5} \times \sqrt{6}} = \frac{1}{2}

We can now solve this equation to find the value of cc.

Let's proceed with the solution. sympy import symbols, Eq, solve, sqrt

Define the variable

c = symbols('c')

Define the equation

equation = Eq((2*c - 3) / (sqrt(c**2 + 5) * sqrt(6)), 1/2)

Solve for c

solutions = solve(equation, c) solutionsThe solution to the equation is approximately c4.67c \approx 4.67.

Would you like further details or have any questions regarding this solution?

Here are some related questions:

  1. How do we calculate the dot product of two vectors?
  2. What is the formula to find the angle between two vectors?
  3. How can we interpret the results of vector magnitudes?
  4. What are some other methods to calculate the angle between vectors?
  5. What are the conditions under which the angle between two vectors is 90°?

Tip: When solving vector problems involving angles, always ensure to check your units and double-check if you are using radians or degrees.

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Math Problem Analysis

Mathematical Concepts

Vectors
Dot Product
Magnitude of a Vector
Trigonometry

Formulas

cos θ = (a · b) / (|a| |b|)
Dot product: a · b = a1b1 + a2b2 + a3b3
Magnitude of a vector: |a| = sqrt(a1^2 + a2^2 + a3^2)

Theorems

Properties of the Dot Product
Trigonometric Relationship for Angles Between Vectors

Suitable Grade Level

Grades 11-12