Math Problem Statement

Evaluate logarithmic functions using the change of base formula, rounding to three decimal places.

Solution

Let's go through each logarithmic function and apply the change of base formula.

The change of base formula for logarithms is: loga(b)=log(b)log(a)\log_a(b) = \frac{\log(b)}{\log(a)} where we can use common logarithms (base 10) for evaluation.

Step-by-Step Solutions

  1. For f(x)=log9(142)f(x) = \log_9(142): f(142)=log(142)log(9)f(142) = \frac{\log(142)}{\log(9)} Using a calculator, this evaluates to approximately f(142)2.379f(142) \approx 2.379.

  2. For g(x)=log4(119)g(x) = \log_4(119): g(119)=log(119)log(4)g(119) = \frac{\log(119)}{\log(4)} Using a calculator, this evaluates to approximately g(119)3.438g(119) \approx 3.438.

  3. For h(x)=log6(51)h(x) = \log_6(51): h(51)=log(51)log(6)h(51) = \frac{\log(51)}{\log(6)} Using a calculator, this evaluates to approximately h(51)2.215h(51) \approx 2.215.

  4. For p(t)=log7(107)p(t) = \log_7(107): p(107)=log(107)log(7)p(107) = \frac{\log(107)}{\log(7)} Using a calculator, this evaluates to approximately p(107)2.652p(107) \approx 2.652.

  5. For f(x)=log3(111)f(x) = \log_3(111): f(111)=log(111)log(3)f(111) = \frac{\log(111)}{\log(3)} Using a calculator, this evaluates to approximately f(111)4.853f(111) \approx 4.853.

Final Table

Logarithmic FunctionRewritten using the change of base formulaEvaluated using the calculator
f(x)=log2(x)f(x) = \log_2(x) at x=8x = 8f(8)=log(8)log(2)f(8) = \frac{\log(8)}{\log(2)}f(8)=3f(8) = 3
f(x)=log9(x)f(x) = \log_9(x) at x=142x = 142f(142)=log(142)log(9)f(142) = \frac{\log(142)}{\log(9)}f(142)2.379f(142) \approx 2.379
g(x)=log4(x)g(x) = \log_4(x) at x=119x = 119g(119)=log(119)log(4)g(119) = \frac{\log(119)}{\log(4)}g(119)3.438g(119) \approx 3.438
h(x)=log6(x)h(x) = \log_6(x) at x=51x = 51h(51)=log(51)log(6)h(51) = \frac{\log(51)}{\log(6)}h(51)2.215h(51) \approx 2.215
p(t)=log7(t)p(t) = \log_7(t) at t=107t = 107p(107)=log(107)log(7)p(107) = \frac{\log(107)}{\log(7)}p(107)2.652p(107) \approx 2.652
f(x)=log3(x)f(x) = \log_3(x) at x=111x = 111f(111)=log(111)log(3)f(111) = \frac{\log(111)}{\log(3)}f(111)4.853f(111) \approx 4.853

Would you like more details on any specific calculation?

Related Questions

  1. How is the change of base formula derived?
  2. What is the difference between common and natural logarithms?
  3. Can logarithmic values be calculated without a calculator?
  4. What are some real-world applications of logarithmic functions?
  5. How does changing the base of a logarithmic function affect its graph?

Tip: Memorizing the change of base formula can help solve logarithmic problems quickly without needing to know complex bases directly.

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Math Problem Analysis

Mathematical Concepts

Logarithms
Change of Base Formula

Formulas

log_a(b) = log(b) / log(a)

Theorems

Change of Base Theorem for Logarithms

Suitable Grade Level

Grades 10-12