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The function provided is \( h(z) = 4z + 7 \). The table asks for completing the rows based on certain values of \( z \) for three questions.

Let's solve the three parts:

### 1. For \( z = 4.9 \):
\[
h(z) = 4(4.9) + 7 = 19.6 + 7 = 26.6
\]

So, the evaluated function value is 26.6.

### 2. For \( z = \frac{1}{2} \):
\[
h\left(\frac{1}{2}\right) = 4\left(\frac{1}{2}\right) + 7 = 2 + 7 = 9
\]

So, the evaluated function value is 9.

### 3. For \( z = \frac{1}{10} \):
\[
h\left(\frac{1}{10}\right) = 4\left(\frac{1}{10}\right) + 7 = 0.4 + 7 = 7.4
\]

So, the evaluated function value is 7.4.

Would you like further clarification or details on these calculations?

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Here are five related questions you can try next:
1. What is \( h(2) \) if \( h(z) = 4z + 7 \)?
2. How do you find the value of \( h(z) \) for negative values of \( z \)?
3. What happens to the function \( h(z) \) as \( z \) increases?
4. How can you determine the inverse of the function \( h(z) \)?
5. What is the slope of the linear function \( h(z) = 4z + 7 \)?

**Tip:** In linear functions like \( h(z) = 4z + 7 \), the coefficient of \( z \) (here, 4) represents the slope or rate of change.

Given the function h(z) = 4z + 7, use the given information to complete the table.

Learn how to evaluate the linear function h(z) = 4z + 7 for specific values of z, such as z = 4.9, z = 1/2, and z = 1/10. This problem covers key concepts like function notation and substitution, suitable for students in Grades 7-9.

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