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The problem states that the function \( f(x) = 2^{x+2} \), and asks to find the value of \( f(-1) + f(0) \).

### Step 1: Calculate \( f(-1) \)
Using the formula \( f(x) = 2^{x+2} \), we substitute \( x = -1 \):

\[
f(-1) = 2^{(-1)+2} = 2^1 = 2
\]

### Step 2: Calculate \( f(0) \)
Now, substitute \( x = 0 \) into the same formula:

\[
f(0) = 2^{0+2} = 2^2 = 4
\]

### Step 3: Add \( f(-1) \) and \( f(0) \)

\[
f(-1) + f(0) = 2 + 4 = 6
\]

Thus, the answer is **B. 6**.

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Would you like further explanation or details? Here are five related questions:

1. How would the answer change if the function was \( f(x) = 3^{x+2} \)?
2. What is the general process to evaluate exponential functions?
3. How do exponential functions behave for negative values of \( x \)?
4. What is the result of \( f(1) + f(2) \) for the given function?
5. Can you describe the transformation of the graph of \( f(x) = 2^{x+2} \)?

**Tip:** Always substitute carefully when working with functions, especially when negative values or exponents are involved.

Jika f(x) = 2^(x+2), maka nilai dari f(-1) + f(0) adalah?

Learn how to evaluate the exponential function f(x) = 2^(x+2) to find the value of f(-1) + f(0) in this math problem. Suitable for students in Grades 9-11.

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