The problem states that the function $f(x) = 2^{x+2}$, and asks to find the value of $f(-1) + f(0)$.

Step 1: Calculate $f(-1)$

Using the formula $f(x) = 2^{x+2}$, we substitute $x = -1$:

$f(-1) = 2^{(-1)+2} = 2^1 = 2$

Step 2: Calculate $f(0)$

Now, substitute $x = 0$ into the same formula:

$f(0) = 2^{0+2} = 2^2 = 4$

Step 3: Add $f(-1)$ and $f(0)$

$f(-1) + f(0) = 2 + 4 = 6$

Thus, the answer is B. 6.

Would you like further explanation or details? Here are five related questions:

1. How would the answer change if the function was $f(x) = 3^{x+2}$?
2. What is the general process to evaluate exponential functions?
3. How do exponential functions behave for negative values of $x$?
4. What is the result of $f(1) + f(2)$ for the given function?
5. Can you describe the transformation of the graph of $f(x) = 2^{x+2}$?

Tip: Always substitute carefully when working with functions, especially when negative values or exponents are involved.