The problem in the image asks for the value of $f(-1) + f(0)$ where the function $f(x) = 2^{x+2}$.

Let's break it down step-by-step:

1. Given function: $f(x) = 2^{x+2}$

2. Calculate $f(-1)$: $f(-1) = 2^{(-1)+2} = 2^1 = 2$

3. Calculate $f(0)$: $f(0) = 2^{0+2} = 2^2 = 4$

4. Sum of $f(-1) + f(0)$: $f(-1) + f(0) = 2 + 4 = 6$

So, the value of $f(-1) + f(0)$ is 6, which corresponds to option B.

Would you like more details on any step, or do you have additional questions?

Here are 5 related questions for further practice:

1. How would you calculate $f(1) + f(2)$ for the same function?
2. What is the general rule for the sum of $f(a) + f(b)$ given $f(x) = 2^{x+2}$?
3. How does the graph of $f(x) = 2^{x+2}$ look compared to $f(x) = 2^x$?
4. What happens to the function $f(x) = 2^{x+2}$ as $x \to \infty$?
5. How can the expression $2^{x+2}$ be rewritten as a product of powers of 2?

Tip: Functions of the form $2^{x+c}$ represent exponential growth, and the constant $c$ shifts the graph horizontally.