The function is given as:

$f(x) = 2^x + 3$

To find $f(-2)$, substitute $x = -2$ into the function:

$f(-2) = 2^{-2} + 3$

Since $2^{-2} = \frac{1}{2^2} = \frac{1}{4}$, the expression becomes:

$f(-2) = \frac{1}{4} + 3$

Now, add the fractions:

$f(-2) = \frac{1}{4} + \frac{12}{4} = \frac{13}{4}$

Thus, the value of $f(-2)$ is:

$f(-2) = \frac{13}{4} = 3.25$

Do you have any questions, or would you like further details on the steps?

Here are 5 related questions:

1. What is the general form of exponential functions?
2. How would $f(x)$ behave as $x$ approaches infinity?
3. What is the derivative of $f(x) = 2^x + 3$?
4. How does the value of the base $2$ affect the growth of the function?
5. What happens to the function $f(x)$ as $x$ becomes negative?

Tip: When evaluating powers of negative exponents, remember they represent fractions!