Math Problem Statement

Let f(x) = 7 + 4x2. Estimate the area under the graph of f, the x-axis, and the lines x = −1 and x = 2 using three rectangles and a right endpoints. Repeat part (a) using a midpoints. M3 = M6 =

Solution

We are tasked with estimating the area under the graph of the function f(x)=7+4x2f(x) = 7 + 4x^2 between x=1x = -1 and x=2x = 2, using two methods: right-endpoint and midpoint approximations with three rectangles.

1. Using Right Endpoints

We divide the interval [1,2][-1, 2] into three equal subintervals. The total width of the interval is:

Δx=2(1)3=1\Delta x = \frac{2 - (-1)}{3} = 1

The right endpoints for these subintervals are:

  • First subinterval: [1,0][-1, 0], right endpoint is x1=0x_1 = 0
  • Second subinterval: [0,1][0, 1], right endpoint is x2=1x_2 = 1
  • Third subinterval: [1,2][1, 2], right endpoint is x3=2x_3 = 2

Now, the function values at the right endpoints are:

  • f(0)=7+4(0)2=7f(0) = 7 + 4(0)^2 = 7
  • f(1)=7+4(1)2=7+4=11f(1) = 7 + 4(1)^2 = 7 + 4 = 11
  • f(2)=7+4(2)2=7+16=23f(2) = 7 + 4(2)^2 = 7 + 16 = 23

The area estimate using right endpoints is:

R3=Δx×(f(0)+f(1)+f(2))=1×(7+11+23)=41square unitsR_3 = \Delta x \times (f(0) + f(1) + f(2)) = 1 \times (7 + 11 + 23) = 41 \, \text{square units}

2. Using Midpoints

We use midpoints of each subinterval for this estimation. The midpoints for the subintervals are:

  • First subinterval [1,0][-1, 0], midpoint is x1=0.5x_1 = -0.5
  • Second subinterval [0,1][0, 1], midpoint is x2=0.5x_2 = 0.5
  • Third subinterval [1,2][1, 2], midpoint is x3=1.5x_3 = 1.5

Now, the function values at the midpoints are:

  • f(0.5)=7+4(0.5)2=7+4(0.25)=8f(-0.5) = 7 + 4(-0.5)^2 = 7 + 4(0.25) = 8
  • f(0.5)=7+4(0.5)2=7+4(0.25)=8f(0.5) = 7 + 4(0.5)^2 = 7 + 4(0.25) = 8
  • f(1.5)=7+4(1.5)2=7+4(2.25)=16f(1.5) = 7 + 4(1.5)^2 = 7 + 4(2.25) = 16

The area estimate using midpoints is:

M3=Δx×(f(0.5)+f(0.5)+f(1.5))=1×(8+8+16)=32square unitsM_3 = \Delta x \times (f(-0.5) + f(0.5) + f(1.5)) = 1 \times (8 + 8 + 16) = 32 \, \text{square units}

Summary:

  • R3=41R_3 = 41 square units (Right-endpoints)
  • M3=32M_3 = 32 square units (Midpoints)

Would you like more details or have any questions?

Here are 5 related questions to expand your understanding:

  1. How would the results change if we used four rectangles instead of three?
  2. How do left-endpoint approximations compare to right-endpoint approximations?
  3. What is the exact area under the curve if we compute the definite integral of f(x)f(x)?
  4. Can you estimate the error between the right-endpoint approximation and the exact integral?
  5. How does the midpoint approximation improve accuracy compared to the right-endpoint approximation?

Tip: When estimating areas using Riemann sums, using more rectangles generally leads to better approximations.

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Math Problem Analysis

Mathematical Concepts

Area Estimation
Riemann Sums
Quadratic Functions

Formulas

Riemann Sum: Area = Δx * (f(x1) + f(x2) + ... + f(xn))
Quadratic Function: f(x) = ax^2 + bx + c

Theorems

Riemann Sum Approximation

Suitable Grade Level

Grade 11-12 (Calculus Introduction)