Math Problem Statement

Consider the function f(x) = 7 + x^2. Estimate the area under f from x = -1 to x = 2 using the methods below. Six rectangles and mid points, entered into a variable M_6.

Solution

To estimate the area under the curve f(x)=7+x2f(x) = 7 + x^2 from x=1x = -1 to x=2x = 2 using six rectangles and the midpoints method, we follow these steps:

1. Partition the Interval

The interval [1,2][-1, 2] has a length of: Δx=2(1)6=36=0.5\Delta x = \frac{2 - (-1)}{6} = \frac{3}{6} = 0.5 Thus, the width of each rectangle is Δx=0.5\Delta x = 0.5.

2. Midpoints

We will now compute the midpoints of each subinterval. For six rectangles, the subintervals are:

  • [1,0.5][-1, -0.5]
  • [0.5,0][-0.5, 0]
  • [0,0.5][0, 0.5]
  • [0.5,1][0.5, 1]
  • [1,1.5][1, 1.5]
  • [1.5,2][1.5, 2]

The midpoints for these intervals are: Midpoints: x1=0.75,x2=0.25,x3=0.25,x4=0.75,x5=1.25,x6=1.75\text{Midpoints: } x_1 = -0.75, x_2 = -0.25, x_3 = 0.25, x_4 = 0.75, x_5 = 1.25, x_6 = 1.75

3. Function Values at Midpoints

Now, calculate the function values f(x)f(x) at these midpoints: f(x)=7+x2f(x) = 7 + x^2 f(0.75)=7+(0.75)2=7+0.5625=7.5625f(-0.75) = 7 + (-0.75)^2 = 7 + 0.5625 = 7.5625 f(0.25)=7+(0.25)2=7+0.0625=7.0625f(-0.25) = 7 + (-0.25)^2 = 7 + 0.0625 = 7.0625 f(0.25)=7+(0.25)2=7+0.0625=7.0625f(0.25) = 7 + (0.25)^2 = 7 + 0.0625 = 7.0625 f(0.75)=7+(0.75)2=7+0.5625=7.5625f(0.75) = 7 + (0.75)^2 = 7 + 0.5625 = 7.5625 f(1.25)=7+(1.25)2=7+1.5625=8.5625f(1.25) = 7 + (1.25)^2 = 7 + 1.5625 = 8.5625 f(1.75)=7+(1.75)2=7+3.0625=10.0625f(1.75) = 7 + (1.75)^2 = 7 + 3.0625 = 10.0625

4. Estimation of Area

Now, multiply each function value by the width Δx=0.5\Delta x = 0.5 and sum them up to get the estimated area: M6=0.5×[f(0.75)+f(0.25)+f(0.25)+f(0.75)+f(1.25)+f(1.75)]M_6 = 0.5 \times [f(-0.75) + f(-0.25) + f(0.25) + f(0.75) + f(1.25) + f(1.75)] M6=0.5×[7.5625+7.0625+7.0625+7.5625+8.5625+10.0625]M_6 = 0.5 \times [7.5625 + 7.0625 + 7.0625 + 7.5625 + 8.5625 + 10.0625] M6=0.5×[47.875]M_6 = 0.5 \times [47.875] M6=23.9375M_6 = 23.9375

Thus, the estimated area under the curve using six rectangles and the midpoint rule is M623.9375M_6 \approx 23.9375.

Would you like further clarification on any steps, or more details?

Related Questions:

  1. How does increasing the number of rectangles affect the accuracy of the midpoint rule?
  2. How is the midpoint rule different from the trapezoidal rule for estimating areas?
  3. Can the exact area under f(x)=7+x2f(x) = 7 + x^2 from x=1x = -1 to x=2x = 2 be computed using integration?
  4. What would the result be if we used the left or right Riemann sum instead of the midpoint rule?
  5. How does the choice of partition points (midpoints vs. endpoints) influence the approximation?

Tip:

For better approximations of areas under curves, increase the number of rectangles or use more advanced methods like Simpson’s rule.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Integral Approximation
Midpoint Rule
Area Under a Curve

Formulas

f(x) = 7 + x^2
Area ≈ Δx × Σf(midpoints)
Δx = (b - a) / n

Theorems

Midpoint Rule for Numerical Integration

Suitable Grade Level

High School (Grades 11-12), Early College