Math Problem Statement

Уравнение прямой, проходящей через точки A(-1, 3) и B(4, 5), имеет вид?

Solution

The image appears to be a mathematical problem involving finding the equation of a line passing through two points, labeled A(1,3)A(-1, 3) and B(4,5)B(4, 5).

To find the equation of the line through these two points, we can use the point-slope form of the line equation, which is given by:

yy1=m(xx1)y - y_1 = m(x - x_1)

where:

  • mm is the slope of the line, calculated as m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}
  • (x1,y1)(x_1, y_1) is a point on the line.

Step 1: Calculate the slope The coordinates of the points are A(1,3)A(-1, 3) and B(4,5)B(4, 5).

The slope mm is:

m=534(1)=25m = \frac{5 - 3}{4 - (-1)} = \frac{2}{5}

Step 2: Use the point-slope form We can use either point for (x1,y1)(x_1, y_1). Let's use point A(1,3)A(-1, 3).

y3=25(x(1))y - 3 = \frac{2}{5}(x - (-1))

Simplify the equation:

y3=25(x+1)y - 3 = \frac{2}{5}(x + 1)

Distribute the 25\frac{2}{5}:

y3=25x+25y - 3 = \frac{2}{5}x + \frac{2}{5}

Step 3: Solve for yy

y=25x+25+3y = \frac{2}{5}x + \frac{2}{5} + 3

Simplify further:

y=25x+175y = \frac{2}{5}x + \frac{17}{5}

Thus, the equation of the line is:

y=25x+175y = \frac{2}{5}x + \frac{17}{5}

Let me know if you'd like more details or further steps explained!


Related Questions:

  1. How do you find the slope between two given points?
  2. How do you use the point-slope form to write the equation of a line?
  3. What is the difference between point-slope form and slope-intercept form?
  4. How do you graph the equation of a line once you have the equation?
  5. What happens to the slope if the points are vertical or horizontal?

Tip: Always check that the slope calculation makes sense — a horizontal line has a slope of 0, and a vertical line has an undefined slope!

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Linear Equations

Formulas

Point-slope form: y - y1 = m(x - x1)
Slope formula: m = (y2 - y1) / (x2 - x1)

Theorems

Basic concepts of linear equations

Suitable Grade Level

Grades 8-10