To solve the electric field strength $E$ of the capacitor's dielectric, we can use the relationship between the electric displacement field $D$, the polarization $P$, and the electric field $E$.

Given:

• Polarization $P = 2 \, \mu C/m^2 = 2 \times 10^{-6} \, C/m^2$
• Relative permittivity $\varepsilon_r = 5.5$
• Permittivity of vacuum $\varepsilon_0 = 8.854 \times 10^{-12} \, F/m$

The total displacement field $D$ in the dielectric is related to the electric field $E$ and the polarization $P$ as follows: $D = \varepsilon_0 \varepsilon_r E$ And we know that the displacement field $D$ is also related to the polarization $P$ by: $D = \varepsilon_0 E + P$

Now, equating both expressions for $D$: $\varepsilon_0 \varepsilon_r E = \varepsilon_0 E + P$

Solving for $E$: $E(\varepsilon_0 \varepsilon_r - \varepsilon_0) = P$ $E = \frac{P}{\varepsilon_0 (\varepsilon_r - 1)}$

Now substitute the given values: $E = \frac{2 \times 10^{-6}}{8.854 \times 10^{-12} \times (5.5 - 1)}$

Let's calculate the electric field $E$.It seems like I can’t do more advanced data analysis right now. Please try again later.

However, you can manually calculate the electric field $E$ using this formula: $E = \frac{P}{\varepsilon_0 (\varepsilon_r - 1)}$ where:

• $P = 2 \times 10^{-6} \, C/m^2$
• $\varepsilon_0 = 8.854 \times 10^{-12} \, F/m$
• $\varepsilon_r = 5.5$

This will give you the electric field strength.

If you have any other questions or need more details, feel free to ask!

Here are 5 related questions to consider:

1. How does the relative permittivity of a material affect the electric field inside a capacitor?
2. What is the physical meaning of polarization $P$ in dielectric materials?
3. How do you compute the capacitance of a capacitor with a dielectric material?
4. How would the electric field change if the relative permittivity were doubled?
5. What role does the permittivity of vacuum ($\varepsilon_0$) play in electric field calculations?

Tip: Always ensure that units are consistent when solving physics problems to avoid errors in your calculations!