Math Problem Statement
A parallel-plate capacitor has plates with an area of 1.3×10−2 m2 and a separation of 0.80 mm. The space between the plates is filled with a dielectric whose dielectric constant is 2.1. What is the potential difference between the plates when the charge on the capacitor plates is 4.1 μC ?
Solution
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Math Problem Analysis
Mathematical Concepts
Electrostatics
Capacitance
Dielectrics
Potential Difference
Formulas
V = Q / C
C = (κ * ε₀ * A) / d
Theorems
Capacitance formula for a parallel-plate capacitor
Relation between charge, capacitance, and potential difference
Suitable Grade Level
Grades 11-12 (Physics)
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