Math Problem Statement

Diagram 6 shows a rectangle ABCD on a Cartesian plane. (a) Show that y = x + 12. (b) Find the area of ΔABC in terms of x and y. (c) Hence, find the coordinates of A given that the area of the rectangle ABCD is 120 units².

Solution

Let's go through each part of the question based on the image you've uploaded.

(a) Show that y=x+12y = x + 12

We need to demonstrate that the coordinates of point A(x,y)A(x, y) satisfy the equation y=x+12y = x + 12.

  • From the diagram, we can see that points A(x,y)A(x, y), B(4,8)B(-4, 8), C(6,2)C(6, -2), and DD form a rectangle, and OO is the origin.
  • Since A(x,y)A(x, y) and B(4,8)B(-4, 8) are on the same diagonal, and diagonals of a rectangle bisect each other at right angles, we can use the midpoint formula and the slope relationship to show that y=x+12y = x + 12.

Let's now apply the midpoint formula and confirm the relationship:

  • The midpoint of ACAC and BDBD is the origin, point O(0,0)O(0, 0).
  • The midpoint formula for A(x,y)A(x, y) and C(6,2)C(6, -2) is: (x+62,y22)=(0,0)\left( \frac{x + 6}{2}, \frac{y - 2}{2} \right) = (0, 0) This gives two equations:
    1. x+62=0\frac{x + 6}{2} = 0x+6=0x + 6 = 0x=6x = -6
    2. y22=0\frac{y - 2}{2} = 0y2=0y - 2 = 0y=2y = 2

However, this suggests the coordinates of AA are incorrect in the context of our earlier steps. Therefore, reviewing this

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Math Problem Analysis

Mathematical Concepts

Geometry
Algebra
Coordinate Geometry
Area of a Triangle

Formulas

Midpoint formula: M = ((x1 + x2)/2, (y1 + y2)/2)
Area of a triangle: A = 1/2 * base * height

Theorems

Properties of Rectangles
Diagonal Bisection Theorem

Suitable Grade Level

Grades 10-12