Math Problem Statement

The dimensions of a rectangle and a triangle are given. The rectangle has a length of 4x cm and a width of (3y + 2) cm. The triangle has a base of 2x cm and a height of (y - 1) cm. You are asked to find: (a) the area of the rectangle, (b) the area of the triangle, and (c) subtract the area of the rectangle from the area of the triangle.

Solution

Let's solve the questions one by one based on the diagram provided:

Part (a): Find the area of the rectangle in terms of xx and yy.

  • The dimensions of the rectangle are given as:

    • Length = 4x4x cm
    • Width = (3y+2)(3y + 2) cm
  • The area ArectA_{\text{rect}} of a rectangle is given by: Arect=Length×WidthA_{\text{rect}} = \text{Length} \times \text{Width} Substituting the given dimensions: Arect=4x×(3y+2)A_{\text{rect}} = 4x \times (3y + 2) Expanding this expression: Arect=12xy+8xcm2A_{\text{rect}} = 12xy + 8x \, \text{cm}^2 Answer for (a): 12xy+8xcm212xy + 8x \, \text{cm}^2


Part (b): Find the area of the triangle in terms of xx and yy.

  • The dimensions of the triangle are given as:

    • Base = 2x2x cm
    • Height = (y1)(y - 1) cm
  • The area AtriA_{\text{tri}} of a triangle is given by: Atri=12×Base×HeightA_{\text{tri}} = \frac{1}{2} \times \text{Base} \times \text{Height} Substituting the given dimensions: Atri=12×2x×(y1)A_{\text{tri}} = \frac{1}{2} \times 2x \times (y - 1) Simplifying: Atri=x(y1)=xyxcm2A_{\text{tri}} = x(y - 1) = xy - x \, \text{cm}^2 Answer for (b): xyxcm2xy - x \, \text{cm}^2


Part (c): Subtract the rectangle’s area from the triangle’s area.

To subtract the area of the rectangle from the area of the triangle, we have: Difference=AtriArect\text{Difference} = A_{\text{tri}} - A_{\text{rect}} Substituting the expressions from parts (a) and (b): Difference=(xyx)(12xy+8x)\text{Difference} = (xy - x) - (12xy + 8x) Expanding and simplifying: Difference=xyx12xy8x\text{Difference} = xy - x - 12xy - 8x Difference=11xy9xcm2\text{Difference} = -11xy - 9x \, \text{cm}^2 Answer for (c): 11xy9xcm2-11xy - 9x \, \text{cm}^2


Let me know if you'd like any further details!


Here are 5 related questions to explore further:

  1. What is the perimeter of the rectangle in terms of xx and yy?
  2. What is the perimeter of the triangle in terms of xx and yy?
  3. If x=2x = 2 and y=3y = 3, what is the numerical value of the area of the rectangle?
  4. What is the total area of the rectangle and the triangle combined in terms of xx and yy?
  5. How would the expressions change if the base of the triangle was 3x3x instead of 2x2x?

Tip: When dealing with geometry problems, always make sure to understand the relationship between dimensions (length, width, base, height) and formulas for area and perimeter!

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometry

Formulas

Area of a rectangle: A = Length × Width
Area of a triangle: A = 1/2 × Base × Height

Theorems

Area calculation formulas

Suitable Grade Level

Grades 8-10