
write logଶ 128 ൌ 𝑥  as an exponential equation and then find the solution. write the exponential equation above the solution 


To express \( \log_2 128 = x \) as an exponential equation, we rewrite it in the form \( 2^x = 128 \).

### Exponential Equation:
\[
2^x = 128
\]

Now, let's solve for \( x \):

Since \( 128 = 2^7 \), we can write:
\[
2^x = 2^7
\]

Equating the exponents:
\[
x = 7
\]

Thus, the solution is \( x = 7 \).

Would you like more details on the steps? Here are 5 related questions for further practice:

1. What is the solution to \( \log_2 64 = x \)?
2. How would you solve \( \log_5 125 = x \) as an exponential equation?
3. Solve \( \log_3 27 = x \) and express it as an exponential equation.
4. What is \( \log_4 256 \) when written as an exponential equation?
5. How would you solve \( \log_7 343 = x \) using exponential form?

**Tip:** To convert any logarithmic equation \( \log_b y = x \) to exponential form, rewrite it as \( b^x = y \).

write log₂ 128 = 𝑥 as an exponential equation and then find the solution. write the exponential equation above the solution

This guide explains how to convert the logarithmic equation log₂ 128 = x into exponential form and solve for x. The solution involves recognizing the exponential relationship 2^x = 128 and solving by equating exponents. Suitable for students in Grades 8-10.

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