We are tasked with solving the equation:

\[
\log_2(x + 1) = 2
\]

### Step-by-Step Solution:

1. **Rewrite the equation in exponential form**:
   The equation \(\log_b(y) = z\) can be rewritten as \(y = b^z\), where \(b\) is the base, \(y\) is the argument of the logarithm, and \(z\) is the exponent.

   Using this rule, we can rewrite the equation \(\log_2(x + 1) = 2\) as:

   \[
   x + 1 = 2^2
   \]

2. **Simplify the equation**:
   Now, simplify the exponent:

   \[
   x + 1 = 4
   \]

3. **Solve for \(x\)**:
   Subtract 1 from both sides:

   \[
   x = 4 - 1
   \]
   \[
   x = 3
   \]

### Final Answer:
\[
x = 3
\]

Would you like further details or have any questions?

Here are 5 related questions to expand your understanding:
1. What is the general formula for converting a logarithmic equation to an exponential equation?
2. How would the solution change if the base of the logarithm were different, say \(\log_3(x + 1) = 2\)?
3. How do we handle logarithmic equations when there are multiple logarithms in the same equation?
4. Can the logarithmic equation \(\log_2(x + 1) = -2\) be solved? What would happen?
5. What are the properties of logarithms that can simplify solving complex equations?

**Tip**: When solving logarithmic equations, always check that the argument of the logarithm (the expression inside the log) is positive, as the logarithm of a negative number is undefined in real numbers.

This solution walks through solving the logarithmic equation log2(x + 1) = 2. Learn how to convert logarithmic equations to exponential form and solve for x step by step. Suitable for students in Grades 9-12.

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