Math Problem Statement

How do you compute the binomial coefficient (��)(kn​)?

Solution

The binomial coefficient (nk)\binom{n}{k}, also known as "n choose k," is a fundamental concept in combinatorics. It represents the number of ways to choose kk elements from a set of nn elements without regard to the order of selection. The formula to compute (nk)\binom{n}{k} is:

(nk)=n!k!(nk)!\binom{n}{k} = \frac{n!}{k!(n-k)!}

where n!n! (n factorial) is the product of all positive integers up to nn, defined as:

n!=n×(n1)×(n2)××1n! = n \times (n-1) \times (n-2) \times \cdots \times 1

and similarly for k!k! and (nk)!(n-k)!.

Steps to Compute (nk)\binom{n}{k}

  1. Calculate the factorial of nn: n!=n×(n1)×(n2)××1n! = n \times (n-1) \times (n-2) \times \cdots \times 1

  2. Calculate the factorial of kk: k!=k×(k1)×(k2)××1k! = k \times (k-1) \times (k-2) \times \cdots \times 1

  3. Calculate the factorial of (nk)(n-k): (nk)!=(nk)×(nk1)××1(n-k)! = (n-k) \times (n-k-1) \times \cdots \times 1

  4. Substitute these values into the binomial coefficient formula: (nk)=n!k!(nk)!\binom{n}{k} = \frac{n!}{k!(n-k)!}

Example Calculation

Let's compute (52)\binom{5}{2}:

  1. Calculate 5!5!: 5!=5×4×3×2×1=1205! = 5 \times 4 \times 3 \times 2 \times 1 = 120

  2. Calculate 2!2!: 2!=2×1=22! = 2 \times 1 = 2

  3. Calculate (52)!=3!(5-2)! = 3!: 3!=3×2×1=63! = 3 \times 2 \times 1 = 6

  4. Substitute into the formula: (52)=5!2!(52)!=1202×6=12012=10\binom{5}{2} = \frac{5!}{2!(5-2)!} = \frac{120}{2 \times 6} = \frac{120}{12} = 10

So, (52)=10\binom{5}{2} = 10.

Simplified Formula for Small Values

For small values of kk relative to nn, it may be more efficient to cancel terms directly rather than computing the full factorials. For example:

(52)=5×42×1=10\binom{5}{2} = \frac{5 \times 4}{2 \times 1} = 10

This approach avoids computing the entire factorials when possible.

Do you want details or have any questions?

Related Questions:

  1. How do binomial coefficients relate to Pascal's triangle?
  2. What are some common properties of binomial coefficients?
  3. How is the binomial coefficient used in the binomial theorem?
  4. Can you provide a real-world application of binomial coefficients?
  5. How do you simplify expressions involving multiple binomial coefficients?
  6. How do binomial coefficients appear in combinatorial proofs?
  7. What is the relationship between binomial coefficients and combinations?
  8. How can you compute binomial coefficients using dynamic programming?

Tip:

When dealing with large factorials, consider using properties of binomial coefficients or computational tools to avoid overflow and improve efficiency.

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Math Problem Analysis

Mathematical Concepts

Combinatorics
Factorials
Binomial Coefficients

Formulas

Binomial coefficient formula: \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \)

Theorems

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Suitable Grade Level

Grades 10-12