Math Problem Statement

Visa att \sum_{k=0}^{n} \binom{n}{k} = 2^n.

Solution

The expression shown in the image is the sum of binomial coefficients:

k=0n(nk)=2n\sum_{k=0}^{n} \binom{n}{k} = 2^n

This is known as the binomial theorem and represents the expansion of the binomial expression (1+1)n(1 + 1)^n. It is derived from the fact that the sum of all the binomial coefficients for a given nn equals 2n2^n.

The formula states that the sum of the binomial coefficients for any nn is equal to 2n2^n, meaning the total number of subsets of a set with nn elements is 2n2^n.

Would you like further explanation or details on how this result is derived?

Here are 5 related questions:

  1. How do you expand (1+1)n(1 + 1)^n using the binomial theorem?
  2. What are binomial coefficients, and how are they calculated?
  3. What is the significance of the result 2n2^n in combinatorics?
  4. How does the binomial expansion relate to Pascal's triangle?
  5. How can the binomial theorem be applied in probability theory?

Tip: To calculate the binomial coefficients (nk)\binom{n}{k}, you can use the formula (nk)=n!k!(nk)!\binom{n}{k} = \frac{n!}{k!(n-k)!}, where n!n! represents the factorial of nn.

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Math Problem Analysis

Mathematical Concepts

Binomial Theorem
Combinatorics
Binomial Coefficients

Formulas

\sum_{k=0}^{n} \binom{n}{k} = 2^n
\binom{n}{k} = \frac{n!}{k!(n-k)!}

Theorems

Binomial Theorem

Suitable Grade Level

Grades 9-12